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Lynna [10]
3 years ago
11

NOT GRADED. FIND THE MEASURE OF THE INDICATER ANGLE IN EACH TRIANGLE.​

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
3 0
If it’s not graded does it really matter but it’s 4042 I think
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Julie bought $8.64 worth of 57-cent stamps and 30-cent stamps. The number of 30-cent stamps was 6 less than the number of 57-cen
Yuri [45]

Answer:

The number of 57-cent stamps that Julie bought is 12

Step-by-step explanation:

Given equation

0.57 s + 0.3 ( s − 6 ) = 8.64

Open bracket

0.57s + 0.3s - 1.8 = 8.64

Collect like terms

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The number of 57-cent stamps that Julie bought is 12

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3 years ago
What is required to name a plane
Ludmilka [50]
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Non-collinear means "not on the same straight line". So these three points can't all lie on the same straight line. If three points do lie on the same straight line, then it is impossible to generate a single unique plane. 
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3 years ago
PLS HELP QUICK!
nikklg [1K]

Answer:

3 x 21

20 x 4 tenths

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please mark me as brainlist please

3 0
2 years ago
How many square feet of outdoor carpet will we need for this hole?
Mamont248 [21]

Answer:

The area of the outdoor carpet = 60 - 6 - 6 = 48 ft²

Step-by-step explanation:

The picture below is what you are referring to .

The whole area of the shape forms a rectangle. A triangle and a  rectangle has been cut off from the whole carpet rectangle. The square ft or area of the carpet is the subtraction of the area of the rectangle and triangle cut off from the whole area of the rectangle .

Area of the rectangle = Lb

where

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b =  5 ft

area = 12 × 5  = 60 ft²

The cut off triangle area

area = 1/2 × base × height

area = 1/2 × 4 × 3

area = 12/2 = 6 ft²

The cut off rectangle area

area = Lb

area = 3 × 2

area = 6 ft²

The area of the outdoor carpet = 60 - 6 - 6 = 48 ft²

7 0
3 years ago
I have <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bdx%7D%7Bdt%7D%20%3D%20%20%5Cfrac%7B5%7D%7Bx%7D%20" id="TexFormula1" title=
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\bf \cfrac{dx}{dt}=\cfrac{5}{t}\quad ,\quad x(0)=7\to &#10;\begin{cases}&#10;f(t)=0\\&#10;t=7&#10;\end{cases}\\\\&#10;-----------------------------\\\\&#10;\displaystyle \int \cfrac{5}{t}\cdot dt\implies 5\int \cfrac{1}{t}\cdot dt\implies 5ln|t|+C= f(t)&#10;\\\\\\&#10;\textit{now, we know when f(t)=0, t=7}\implies 5ln|7|+C=0&#10;\\\\\\&#10;C=-5ln(7)&#10;\\\\\\&#10;thus\implies \boxed{5ln|t|-5ln(7)=f(t)=x}

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