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blondinia [14]
3 years ago
15

Re-write the quadratic function below in Standard Formy=−7(x+1)^2+5

Mathematics
1 answer:
Yuri [45]3 years ago
3 0

Answer:

y=-7x^2-14x-2

Step-by-step explanation:

Hope this helpz

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Find the equation of the line parallel to y=5x+1 that contains the point (4,8)
astraxan [27]

The equation of a parallel line will have the same x-term, but a different constant (y-intercept). The required value can be found by putting the given point values in to the equation to see what it needs to be.

... y = 5x + ___

... 8 = 5·4 + ___

... 8 - 20 = -12 = ___

Your equation is ...

... y = 5x -12

4 0
3 years ago
5(y - 3) = -2<br>pls answer.​
muminat

Answer:

y= 2.6

Step-by-step explanation:

5 0
4 years ago
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the average lifespan of a horse is 40 years, which is five times longer than the average lifespan of a guinea pig. Use the bar d
polet [3.4K]
All you have to do is divide 40 by five and you've got your answer. I don't have the required diagram, but that would basically mean that the average lifespan of a guinea pig is about eight years, which is being generous in reality (they usually live for about 4-8 years in real life).
3 0
3 years ago
What is <br> 3x + -5 = x + 1 <br> i need the answer asap!!!!!
Flauer [41]

Answer:

3x-5=x+1

2x-5=1

2x=6

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Let me know if this helps!

6 0
3 years ago
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Suppose x, y and z are integers. Prove that, if 3x−y + 5z is even, then at least one of x, y or z is even.
Elden [556K]

Given:

x, y and z are integers.

To prove:

If 3x-y+5z is even, then at least one of x, y or z is even.

Solution:

We know that,

Product of two odd integers is always odd.          ...(i)

Difference of two odd integers is always even.          ...(ii)

Sum of an even integer and an odd integer is odd.      ...(iii)

Let as assume x, y and z all are odd, then 3x-y+5z is even.

3x is always odd.          [Using (i)]

5z is always odd.          [Using (i)]

3x-y is always even.       [Using (ii)]

(3x-y)+5z is always odd.       [Using (iii)]

3x-y+5z is always odd.

So, out assumption is incorrect.

Thus, at least one of x, y or z is even.

Hence proved.

4 0
3 years ago
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