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algol13
3 years ago
10

Y=-3/4x+9 y=-1/2x+8 x=

Mathematics
1 answer:
Artemon [7]3 years ago
7 0

Answer:

yedhxncj

Step-by-step explanation:

tgrfhhffbvxvxxnndhndhfdhduduriI'm playing with my pu**y find me here - www.nowdate.fun

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It would be -8,6, and 4
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18 students are going on a field trip and 10 students are staying at school. What is the ratio of the number of students who are
galben [10]

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because 18 students are going and 10 are staying

7 0
2 years ago
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What is the simplest form for 13/8
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6 0
3 years ago
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Explain why f(x) = x^2+4x+3/x^2-x-2 is not continuous at x = -1.
liberstina [14]

Answer:

The value of x = -1 makes the denominator of the function equal to zero. That is why this value is not included in the domain of f(x)

Step-by-step explanation:

We have the following expression

f(x) = \frac{x^2+4x+3}{x^2-x-2}

Since the division between zero is not defined then the function f(x) can not include the values of x that make the denominator of the function zero.

Now we search that values of x make 0 the denominator factoring the polynomial x^2-x-2

We need two numbers that when adding them get as a result -1 and when multiplying those numbers, obtain -2 as a result.

These numbers are -2 and 1

Then the factors are:

(x-2) (x + 1)

We do the same with the numerator

x^2+4x+3

We need two numbers that when adding them get as a result 4 and when multiplying those numbers, obtain 3 as a result.

These numbers are 3 and 1

Then the factors are:

(x+3)(x + 1)

Therefore

f(x) = \frac{(x+3)(x+1)}{(x-2)(x+1)}

Note that \frac{(x+1)}{(x+1)}=1 only if x \neq -1

So since x = -1 is not included in the domain the function has a discontinuity in x = -1

3 0
3 years ago
Solve the inequality<br> 7x&lt;5x-8
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Minust 5x both sides
7x-5x<5x-5x-8
2x<-8
divide by 2 both sides
x<-4
6 0
3 years ago
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