All categories

3 years ago

Suppose y varies inversely with x, and y = 25 when x = 1/5. What is the value of y when x = 5 ?

Mathematics

1 answer:

34kurt3 years ago

8 0

Answer:

y = 1

Step-by-step explanation:

Given that y varies inversely with x then the equation relating them is

y = $\frac{k}{x}$ ← k is the constant of variation

To find k use the condition y = 25 when x = $\frac{1}{5}$ , then

25 = $\frac{k}{\frac{1}{5} }$ = 5k ( divide both sides by 5 )

5 = k

y = $\frac{5}{x}$ ← equation of variation

When x = 5, then

y = $\frac{5}{5}$ = 1

You might be interested in

What are the zeros of the quadratic function f(x) = 6x2 – 24x + 1?

MAXImum [283]

Answer:

Step-by-step explanation:

6*2-24x+1=

12+1=24x

x+1= 24/12

x+1=2

x=2-1

x=1

4 0

3 years ago

PLEASE HELP! ITS DUE SOON AND IM STUCK ON THE LASY QUESTION!

Andrej [43]

Answer:

2k + 4 > k + 11

Step-by-step explanation:

Keywords:

more - addition

twice - multiplication

greater than - >

sum - addition

4 more than twice the number k

2k + 4

Greater than

Sum of k and 11

k + 11

2k + 4 > k + 11

Solve for k if needed.

2k + 4 > k + 11

2k > k + 7

k > 7

Best of Luck!

6 0

3 years ago

Simplify the sum. d^2-9d+20/d^2-3d-10 plus d^2-2d-8/d^2+4d-32

dimaraw [331]

For this case what you should do is follow the following steps:
1) factorize numerator and denominator of both expressions.
2) cancel similar terms
3) add both fractions by cross product
4) Rewrite the numerator and denominator.
Answer:
See attached image.