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3 years ago

A^2×c^2/c^2×d^2+bc/ad reduce the algebraic

Mathematics

1 answer:

Leona [35]3 years ago

3 0

Answer:

$\frac{a^2*c^2}{c^2*d^2}+\frac{bc}{ad}= \frac{a^3 + bcd}{ad^2}$

Step-by-step explanation:

Given

$\frac{a^2*c^2}{c^2*d^2}+\frac{bc}{ad}$

Required

Simplify

We have:

$\frac{a^2*c^2}{c^2*d^2}+\frac{bc}{ad}$

Cancel out $c^2$

$\frac{a^2*c^2}{c^2*d^2}+\frac{bc}{ad}= \frac{a^2}{d^2}+\frac{bc}{ad}$

Take LCM

$\frac{a^2*c^2}{c^2*d^2}+\frac{bc}{ad}= \frac{a^3 + bcd}{ad^2}$

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How do you write 1,201,341,567 in expanded form

pav-90 [236]

Expanded Form Would Be:
1,000,000,000 +200,000,000 +0 +1,000,000 +300,000 +40,000 +1,000 +500 +60 +7
Expanded Factors Form:
1 ×1,000,000,000 +2 ×100,000,000 +0 ×10,000,000 +1 ×1,000,000 +3 ×100,000 +4 ×10,000 +1 ×1,000 +5 ×100 +6 ×10 +7 ×1
Expanded Exponential Form Would Be:
1 × 109+2 × 108+0 × 107+1 × 106+3 × 105+4 × 104+1 × 103+5 × 102+6 × 101+7 × 100
Word Form Would Be:

<span>one billion, two hundred one million, three hundred forty-one thousand, five hundred sixty-seven</span>

5 0

3 years ago

Read 2 more answers

Whats the answer for this...?<br> Ive tried 6 times in total, i just gave up :l

BartSMP [9]

Answer:

-1 3/8 / -1 4/7 = -11/8 / -11/7 = -11+7/56 + -11+8/56 = -4/56-3/56= -7/56=-1/8

3 0

2 years ago

he blood platelet counts of a group of women have a bell-shaped distribution with a mean of 247.3 and a standard deviation of 6

Ulleksa [173]

Answer:

The approximate percentage of women with platelet counts within 3 standard deviations of the mean is 99.7%.

Step-by-step explanation:

We are given that the blood platelet counts of a group of women have a bell-shaped distribution with a mean of 247.3 and a standard deviation of 60.7.

Let X = <em>t</em><u><em>he blood platelet counts of a group of women</em></u>

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean = 247.3

$\sigma$ = standard deviation = 60.7

Now, according to the empirical rule;

68% of the data values lie within one standard deviation of the mean.

95% of the data values lie within two standard deviations of the mean.

99.7% of the data values lie within three standard deviations of the mean.

Since it is stated that we have to calculate the approximate percentage of women with platelet counts within 3 standard deviations of the mean, or between 65.2 and 429.4, i.e;

z-score for 65.2 = $\frac{X-\mu}{\sigma}$

= $\frac{65.2-247.3}{60.7}$ = -3

z-score for 429.4 = $\frac{X-\mu}{\sigma}$

= $\frac{429.4-247.3}{60.7}$ = 3

So, it means that the approximate percentage of women with platelet counts within 3 standard deviations of the mean is 99.7%.

4 0

3 years ago

2x-5y=-28 find the value of y when x equals -19

nydimaria [60]

<h3>Question:</h3>

2x-5y=-28 find the value of y when x equals -19

<h3>Answer:</h3>

Y = - 2

<h3>Step-by-step explanation:</h3>

First you plug in -19 where x is 2(-19)-5y = -28

Remove parentheses -2 · 19-5y= -28

Multiply -2 by 19 -38-5y= -28

Add 38 to both sides -5y = 10

Divide both sides by -5 [tex]\frac{-5y}{-5} =\frac{10}{-5}[/tex

you will get -2 which is the answer.

Hope this helped!

8 0

4 years ago

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What is the volume of the cube below?

svlad2 [7]

Answer:

Step-by-step explanation:

volume = side³

v = 3³

v = 27

i dont know how to convert to whatever <em>h </em>is so this is the best answer i can give

3 0

2 years ago

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A^2×c^2/c^2×d^2+bc/ad reduce the algebraic ​

A^2×c^2/c^2×d^2+bc/ad reduce the algebraic