The measures of two complementary angles are 64 degrees and 26 degrees
<h3><u>Solution:</u></h3>
Let the larger angle be "a" and smaller angle be "b"
<em>Two angles are Complementary when they add up to 90 degrees</em>
so we get,
a + b = 90 ------ eqn 1
Given that measure of the larger angle is 12 more than twice the measure of the smaller angle
larger angle = 12 + 2(smaller angle)
a = 12 + 2b --- eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to get values of "a" and "b"</u></em>
Substitute eqn 2 in eqn 1
12 + 2b + b = 90
12 + 3b = 90
3b = 90 - 12
3b = 78
<h3>b = 26</h3>
Therefore from eqn 2,
a = 12 + 2b
a = 12 + 2(26)
a = 12 + 52
<h3>a = 64</h3>
Thus the measures of two complementary angles are 64 degrees and 26 degrees
Answer:
Ok tell me what you need so I can help
Answer:
-3a + 4ab
Step-by-step explanation:
-5a + 2a = -3a
-6ab + 10ab = 4ab
3x+3-x+(-7)>6
combine like terms on left side
2x-4>6
add 4 to both sides 2x>10
x=10/2 = 5
x>5
X=1 y=-2 I am sure I did it
