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garik1379 [7]
2 years ago
5

PLEASE Factor the polynomial completely 8v^2-60v-32

Mathematics
1 answer:
lord [1]2 years ago
3 0
The answer is (4v+2)*(2v-16)
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8n^2-4(7m^3+5n^2)<br> help
Rasek [7]
Hello there!


8m² - 4(7m³ + 5n²)

You wanna start by using the distributive property

=8n² - (-4)(7m³) + (-4)(5n²)

= 8n² - 28m³ - 20n²

= -28m³ - 12m²
7 0
2 years ago
Which expression is equivalent to (3−2^2) 5 ? 5−3^2 5−2^2 2^2−5 ​ 3^2−5
tamaranim1 [39]
Well (3-2^2)5 = -5
and 5-3^2=-4
5-2^2=1
2^2-5=-1
3^2-5=4
but if you have to multiply them by 5 as well then (2^2-5)5=-5
8 0
3 years ago
The graph shows the number of handbags that mandy made in one day.What are the variables? Describe how the variables are related
tankabanditka [31]
The variables are: time(the independent variable or (x) variable) and number of handbags (the dependent variable or (y) variable). The variables helps to plot an accurate points on the graph.
8 0
3 years ago
Read 2 more answers
Jake is taking four of his friends to dinner. At the restaurant, a meal, side item, dessert, and drink cost $5.60. The first dri
KonstantinChe [14]
It's the third one! Hope this helps:3
3 0
2 years ago
A random sample of 100 people was taken. Eighty of the people in the sample favored Candidate A. We are interested in determinin
riadik2000 [5.3K]

Answer:

Option b - not significantly greater than 75%.

Step-by-step explanation:

A random sample of 100 people was taken i.e. n=100

Eighty of the people in the sample favored Candidate i.e. x=80

We have used single sample proportion test,

p=\frac{x}{n}

p=\frac{80}{100}

p=0.8

Now we define hypothesis,

Null hypothesis H_0 : candidate A is significantly greater than 75%.

Alternative hypothesis H_1 : candidate A is not significantly greater than 75%.

Level of significance \alpha=0.05

Applying test statistic Z -proportion,

Z=\frac{\widehat{p}-p_0}{\sqrt{\frac{p_0(1-p_0)}{n}}}

Where, \widehat{p}=80\%=0.80 and p=75%=0.75

Substitute the values,

Z=\frac{0.80-0.75}{\sqrt{\frac{0.75(1-0.75)}{100}}}

Z=\frac{0.80-0.75}{\sqrt{\frac{0.1875}{100}}}

Z=\frac{0.05}{0.0433}

Z=1.1547

The p-value is

P(Z>1.1547)=1-P(Z

P(Z>1.1547)=1-0.8789

P(Z>1.1547)=0.1241

Now, the p-value is greater than the 0.05.

So we fail to reject the null hypothesis and conclude that the A is not significantly greater than 75%.

Therefore, Option b is correct.

7 0
3 years ago
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