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3 years ago

Someone plssss helppppp i need it finished in like 20 min plsss help

Mathematics

1 answer:

denis23 [38]3 years ago

3 0

Answer:

number of guest tickets, g, is 100 tickets

number of student tickets, s, is 125 tickets

Step-by-step explanation:

Given;

total number of tickets sold, t = 225 tickets

cost of each guest ticket, = $5.5

cost of each student ticket, = $3.5

total cost of the tickets, Tc = $987.5

number of guest tickets = g

number of student tickets, = s

g(5.5) + s(3.5) = 987.5 ------- (1)

g + s = 225 ----------- (2)

From equation (2); s = 225 - g

Substitute the value of g in equation (1)

5.5g + 3.5(225 - g) = 987.5

5.5g + 787.5 - 3.5g = 987.5

5.5g - 3.5g = 987.5 - 787.5

2g = 200

g = 200 / 2

g = 100 tickets

Then, s = 225 - g

s = 225 - 100

s = 125 tickets

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2. Tennis rackets can be packaged in cartons holding 2 rackets cach or in

Liula [17]

Answer:

There were 14 cartons of size 2 rackets and 24 cartons of size 3 rackets

Step-by-step explanation:

Assume that the number of cartons holding 2 rackets is x and the number of cartons holding 3 rackets is y

∵ There are x cartons of 2 rackets

∵ There are y cartons of 3 rackets

∵ They used 38 cartons

∴ x + y = 38 ⇒ (1)

∵ They packed a total of 100 rackets

∴ 2x + 3y = 100 ⇒ (2)

Let us solve the system of equations

→ Multiply equation (1) by -2 to make the coefficients of x in

the equations equal in values and different is signs

∵ -2(x) + -2(y) = -2(38)

∴ -2x - 2y = -76 ⇒ (3)

→ Add equations (2) and (3)

∴ y = 24

→ Substitute the value of y in equation (1) or (2) to find x

∵ x + 24 = 38

→ Subtract 24 from both sides

∴ x + 24 - 24 = 38 - 24

∴ x = 14

There were 14 cartons of size 2 rackets and 24 cartons of size 3 rackets

7 0

3 years ago

9. The Strawberry Festival is finally here! Mrs.

chubhunter [2.5K]

$\left \{ {{- \atop {2(21.5-2y)+2y=30}} \right.$ Answer:

Step-by-step explanation:

x= gourmet pretzels

y= boxes of strawberries

system will be:

$\left \{ {{2x+4y=43 \atop {2x+2y=30}} \right.$

$\left \{ {{2x+4y=43 \atop {2x+2y=30}} \right.$ $\left \{ {{x=21.5-2y \atop {2x+2y=30}} \right.$ $\left \{ {{- \atop {2(21.5-2y)+2y=30}} \right.$ $\left \{ {{- \atop {43-4y+2y=30}} \right.$ $\left \{ {{- \atop {-4y+2y=30-43}} \right.$ $\left \{ {{- \atop {-2y=-13}} \right.$ $\left \{ {{- \atop {y=\frac{13}{2} }} \right.$ $\left \{ {x=21.5-2(6.5)}} \atop {y=6.5}} \right.$ $\left \{ {{x=8.5} \atop {y=6.5}} \right.$