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GuDViN [60]
3 years ago
8

How many grams of N2 gas are present in 1.13 L of gas at 2.09 atm and 291 K?

Chemistry
1 answer:
solong [7]3 years ago
6 0

Answer:

Mass= 2.77g

Explanation:

Applying

P=2.09atm, V= 1.13L, R= 0.082, T= 291K, Mm of N2= 28

PV=nRT

NB

Moles(n) = m/M

PV=m/M×RT

m= PVM/RT

Substitute and Simplify

m= (2.09×1.13×28)/(0.082×291)

m= 2.77g

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nexus9112 [7]
Because you are never adding more than the substances created, nor are you creating any, but should a chemical reaction take place you could see the liquid change form into a gaseous state and that would result a loss of the liquid volume.
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2 years ago
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Sonbull [250]

Answer:39 min

Explanation:

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2 years ago
What is a change in a substance that does not involve the identity of the substance
GenaCL600 [577]

The answer to this would be a physical change. Physical changes are changes that affect the form of a chemical substance, but not the chemical composition itself. Hope this helped!


6 0
3 years ago
Read 2 more answers
Under which conditions of temperature and pressure does a real gas behave most like an ideal gas
Veseljchak [2.6K]
At higher temperature, and lower pressure. 
4 0
3 years ago
Write the Ka expression for an aqueous solution of hydrofluoric acid: (Note that either the numerator or denominator may contain
damaskus [11]

Answer:

Ka = ( [H₃O⁺] . [F⁻] ) / [HF]

Explanation:

HF is a weak acid which in water, keeps this equilibrium

HF (aq)  +  H₂O (l)  ⇄  H₃O⁺ (aq)  +  F⁻ (aq)      Ka

2H₂O (l)  ⇄  H₃O⁺ (l)  +  OH⁻ (aq)   Kw

HF is the weak acid

F⁻ is the conjugate stron base

Let's make the expression for K

K = ( [H₃O⁺] . [F⁻] ) / [HF] . [H₂O]

K . [H₂O] = ( [H₃O⁺] . [F⁻] ) / [HF]

K . [H₂O] = Ka

Ka, the acid dissociation constant, includes Kwater.

4 0
2 years ago
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