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GuDViN [60]
3 years ago
8

How many grams of N2 gas are present in 1.13 L of gas at 2.09 atm and 291 K?

Chemistry
1 answer:
solong [7]3 years ago
6 0

Answer:

Mass= 2.77g

Explanation:

Applying

P=2.09atm, V= 1.13L, R= 0.082, T= 291K, Mm of N2= 28

PV=nRT

NB

Moles(n) = m/M

PV=m/M×RT

m= PVM/RT

Substitute and Simplify

m= (2.09×1.13×28)/(0.082×291)

m= 2.77g

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How many neutrons does an element have if its atomic number is 41 and its mass number is 170?
BARSIC [14]

atomic number = protons.

protons+neutrons=atomic mass.

170 (mass) - 41 (proton/number) = 129

that should be ur answer. I hope this helps!

7 0
3 years ago
How many miles could you drive for $7.90 if the gas mileage of your car is 14km/liter of gas and the price is $1.29/gal? (1.61km
navik [9.2K]

Answer:

6.124 gallons

Explanation:

3 0
2 years ago
What’s the relationship between homozygous and pure?
Ulleksa [173]

Answer:

A pure trait is also known as a homozygous trait. Homozygous traits are either a combination of the same two dominant alleles or the same two recessive alleles. A hybrid trait is also known as a heterozygous trait, and is the pairing of a dominant and recessive allele.

Explanation:each possible combo has a term for it. When we have two capital or two lowercase letters in the GENOTYPE

5 0
3 years ago
A concentration cell consists of two sn/sn2+ half-cells. the electrolyte in compartment a is 0.24 m sn(no3)2. the electrolyte in
Vikentia [17]
A:-      sn(s) =>  Sn +2(0.24 M) + 2e-
B:-     Sn +2 (0.87 M) +2e-  =>   Sn(s) 

solution will become more concentrated and solution B become less concentrated 

Sn(s)+ Sn +2(0.87 ) ----> Sn(s) + Sn  +2(0.24)
E  =   Eo  -   0.0592 / 2 * log   [   (0.24 / 0.87 ) ]
E  = 0.0   -   0.0592 / 2   *   log ( 0.275) 
( n=2 two electrons are transferred)

E =  -0.0296 *  ( - 0.560) 
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4 0
3 years ago
Provide an example of a substance with non-polar bonds
LenaWriter [7]

Answer:

Tin (IV) chloride (SnCl4)...Methane(CH4)

Explanation:

all the dipole moments of the bonds tend to cancel each other out...hence leaving the substance non-polar

5 0
3 years ago
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