Advantages and disadvantages of screen reading
2 answers:
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Answer:
Explanation:
The following code is written in Java, it prompts the user to enter 10 integers and saves them to an ArrayList. Then it prompts for 5 strings and saves them to another ArrayList. Then, it calls the sort method and adds the lists as parameters. Finally, it prints out both lists completely sorted in ascending order.
import java.util.ArrayList;
import java.util.Scanner;
class Division{
public static double division(double a, double b) throws Exception {
if(b == 0)
//throw new Exception("Invalid number.");
return (a / b);
return a / b;
}
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
ArrayList<Integer> mylist2 = new ArrayList<>();
for (int x = 0; x < 10; x++) {
System.out.println("Please Enter a Number: ");
int number = in.nextInt();
mylist2.add(number);
}
ArrayList<String> mylist = new ArrayList<>();
for (int x = 0; x < 5; x++) {
System.out.println("Please Enter a Word: ");
String word = in.nextLine();
mylist.add(word);
}
sort(mylist);
sort(mylist2);
for (String x: mylist) {
System.out.print(x + ", ");
}
System.out.println("");
for (int x: mylist2) {
System.out.print(x + ", ");
}
}
public static <E extends Comparable<E>> ArrayList<E> sort(ArrayList<E> list) {
E temp;
if (list.size()>1) // check if the number of orders is larger than 1
{
for (int x=0; x<list.size(); x++) // bubble sort outer loop
{
for (int i=0; i < list.size() - x - 1; i++) {
if (list.get(i).compareTo(list.get(i+1)) > 0)
{
temp = list.get(i);
list.set(i,list.get(i+1) );
list.set(i+1, temp);
}
}
}
}
return list;
}}
