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frutty [35]
3 years ago
5

Big data are used to _____. Select 3 options.

Computers and Technology
1 answer:
Anon25 [30]3 years ago
8 0

Answer:

Big data are used to _____. Select 3 options.

understand people’s hobbies

analyze people’s interests

make decisions about marketing

Explanation:

100%

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Explain the process of a for loop and how it is used in code
marshall27 [118]

Ex:

FOR Count= 1 TO 50

.......................

Body

......................

NEXT

Next keeps incrementing count by 1

Hope it helps

4 0
3 years ago
How fast can the winds blow in a tornado?
sp2606 [1]
Over 200 mph generally now I says 300 mph
6 0
4 years ago
Read 2 more answers
Write a for loop that will print the values 1 to 20 while skipping the odd numbers (2,4,6,8,10,12,14,16,18,20):
DochEvi [55]

<u>Answer:</u>

<em>void main ( )  </em>

<em> {  </em>

<em> int counter;  </em>

<em>  cout<<""Even numbers between 1 to 20 are:""<<endl ;  </em>

<em> //Method 1 </em>

<em>  for (counter = 1; counter <= 20; counter++)  </em>

<em>  {  </em>

<em>    if ( counter%2 == 0)  </em>

<em>   {   </em>

<em>     cout<<counter<<""\t""<<endl ;  </em>

<em>   }  </em>

<em>  }  </em>

<em>//Method 2 – simplest one </em>

<em>for (counter = 2; counter <= 20;)  </em>

<em>  {  </em>

<em>     cout<<counter<<""\t""<<endl ;  </em>

<em>counter = counter + 2; </em>

<em>    </em>

<em>  } </em>

<em> </em>

<em>  return 0;  </em>

<em>} </em>

<u>Explanation:</u>

In this, Method 1 runs a for loop and check whether each number is divided by 2. If yes, then printed otherwise it is skipped.

In the second method, it runs for loop only for even numbers. <em>This is obtained by incrementing the counter by 2. </em>

6 0
3 years ago
What are some games you have played on the internet? Give atleast two. (Some computer come up with games allready on them where
Nadusha1986 [10]

Answer:

Geometry Dash and Slope Unblocked are my favorites.

Explanation:

4 0
3 years ago
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Jake's rally car averages 130 km/h. Jake entered car iñ a 450 km race. if the race started at 1 PM , about what time he would li
guajiro [1.7K]

The rule for object moving at constant (average) velocity is

s=vt

where s is the space, v is the velocity and t is time. We deduce that

t=\dfrac{s}{v}

So, to travel 450km at a rate of 130km/h, it will take

t=\dfrac{450}{130}\approx 3.5

So, starting 1PM, after about 3.5 hours it wil be 4.30PM

8 0
3 years ago
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