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muminat
3 years ago
13

What is the poH of a 2.6 x 10-6 M H+ solution? pOH = [?]

Chemistry
2 answers:
vladimir2022 [97]3 years ago
7 0

Answer:

8.41

Explanation:

KatRina [158]3 years ago
5 0

Answer:

pOH = 8.41

Explanation:

From the question given above, we obtained the following information:

Concentration of Hydrogen ion [H⁺] = 2.6×10¯⁶ M

pOH =?

Next, we shall determine the pH of the solution. This can be obtained as follow:

Concentration of Hydrogen ion [H⁺] = 2.6×10¯⁶ M

pH =?

pH = – Log [H⁺]

pH = – Log (2.6×10¯⁶)

pH = 5.59

Finally, we shall determine the pOH of the solution. This can be obtained as follow:

pH = 5.59

pOH =?

pH + pOH = 14

5.59 + pOH = 14

Collect like terms

pOH = 14 – 5.59

pOH = 8.41

Therefore, the pOH of the solution is 8.41

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What is the balance equation of Aluminum metal and iron (III) oxide react to form aluminum oxide and iron metal?
Tcecarenko [31]

Answer:

2Al3+ + Fe2O3 -> Al2O3 + 2Fe3+

Explanation:

7 0
4 years ago
What is the total number of different elements present in NH4NO3
Nookie1986 [14]
 <span>3 elements 
Nitrogen 
Hydrogen 
Oxygen 

2 nitrogen 4 hydrogen and 3 oxygens 
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4 0
3 years ago
Read 2 more answers
3) How many moles of solute are dissolved in 1.5 L of a 0.80 M solution? * 10 points
Mrrafil [7]

Answer:

1.2

Explanation:

Molarity = moles/volume

to find the moles, you must multiply both sides by volume

so, take 1.5 L * 0.80 M

this equals 1.2 :)

7 0
3 years ago
What is the mass of HCL is consumed by the reaction of 1.5 mole of magnesium
photoshop1234 [79]

Answer: 109.5g

Explanation:

Mg + 2HCl —> MgCl2 + H2

From the equation,

1mole of Mg required 2moles of HCl

Therefore 1.5moles of Mg will require = 1.5 x 2 = 3 moles of HCl.

Molar Mass of HCl = 1+35.5 =36.5g/mol

Mass conc. Of HCl = 3 x 36.5 = 109.5g

3 0
3 years ago
Write the overall, balanced molecular equation and indicate which element is oxidized and which is reduced for the following rea
REY [17]

Explanation:

Mg(s) + Cr(C2H3O2)3 (aq)

Overall, balanced molecular equation

Mg(s) + Cr(C2H3O2)3(aq) --> Mg(C2H3O2)3(aq) + Cr(s)

To identify if an element has been reduced or oxidized, the oxidation number is observed in both the reactant and product phase.

An increase in oxidation number denotes that the element has been oxidized.

A decrease in oxidation number denotes that the element has been reduced.

Oxidation number of Mg:

Reactant - 0

Product - +3

Oxidation number of Cr:

Reactant - +3

Product - 0

Note: C2H3O2 is actually acetate ion; CH3COO- The oxidatioon number of C, H and O do not change.

Oxidized : Mg

Reduced : Cr

7 0
3 years ago
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