All categories

3 years ago

What is the poH of a 2.6 x 10-6 M H+ solution? pOH = [?]

Chemistry

2 answers:

vladimir2022 [97]3 years ago

7 0

Answer:

8.41

Explanation:

KatRina [158]3 years ago

5 0

Answer:

pOH = 8.41

Explanation:

From the question given above, we obtained the following information:

Concentration of Hydrogen ion [H⁺] = 2.6×10¯⁶ M

pOH =?

Next, we shall determine the pH of the solution. This can be obtained as follow:

Concentration of Hydrogen ion [H⁺] = 2.6×10¯⁶ M

pH =?

pH = – Log [H⁺]

pH = – Log (2.6×10¯⁶)

pH = 5.59

Finally, we shall determine the pOH of the solution. This can be obtained as follow:

pH = 5.59

pOH =?

pH + pOH = 14

5.59 + pOH = 14

Collect like terms

pOH = 14 – 5.59

pOH = 8.41

Therefore, the pOH of the solution is 8.41

You might be interested in

3 Cu + 8HNO3 g 3 Cu(NO3)2 + 2 NO + 4 H2O

Ksivusya [100]

Considering the reaction stoichiometry, the amount of moles of NO that is produced when 27 moles of HNO₃ react is 6.75 moles.

<h3 /><h3>Reaction stoichiometry</h3>

The balanced reaction is:

3 Cu + 8 HNO₃ → 3 Cu(NO₃)₂ + 2 NO + 4 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Cu: 3 moles
HNO₃: 8 moles
Cu(NO₃)₂: 3 moles
NO: 2 moles
H₂O: 4 moles

<h3>Amount of moles of NO produced</h3>

It is possible to determine the the amount of moles of NO produced by a rule of three: if by stoichiometry 8 moles of HNO₃ produce 2 moles of NO, if 27 moles of HNO₃ react how many moles of NO will be formed?

$amount of moles of NO=\frac{27 moles of HNO_{3} x 2 moles of NO}{8 moles of HNO_{3}}$

<u><em>amount of moles of NO= 6.75 moles</em></u>

In summary, the amount of moles of NO that is produced when 27 moles of HNO₃ react is 6.75 moles.

Learn more about reaction stoichiometry:

<u>brainly.com/question/11999193</u>

<u>brainly.com/question/15111313?referrer=searchResults</u>

<u>brainly.com/question/9926203?referrer=searchResults</u>

<u>brainly.com/question/6061451?referrer=searchResults</u>

4 0

3 years ago

form a hypothesis sharks don't have swim bladders and must move constantly or they sink. hypothesize about the amount of food th

MariettaO [177]

Sharks have to move often and not slowly and have to eat more than a bony fish

3 0

3 years ago

In the activity, click on the E∘cell and Keq quantities to observe how they are related. Use this relation to calculate Keq for

olga_2 [115]

<u>Answer:</u> The $E^o_{cell}\text{ and }K_{eq}$ of the reaction is 0.78 V and $2.44\times 10^{26}$ respectively.

<u>Explanation:</u>

For the given half reactions:

Oxidation half reaction: $Fe(s)\rightarrow Fe^{2+}+2e^-;E^o_{Fe^{2+}/Fe}=-0.44V$

Reduction half reaction: $Cu^{2+}+2e^-\rightarrow Cu(s);E^o_{Cu^{2+}/Cu}=0.34V$

Net reaction: $Fe(s)+Cu^{2+}\rightarrow Fe^{2+}+Cu(s)$

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Putting values in above equation, we get:

$E^o_{cell}=0.34-(-0.44)=0.78V$

To calculate equilibrium constant, we use the relation between Gibbs free energy, which is:

$\Delta G^o=-nfE^o_{cell}$

and,

$\Delta G^o=-RT\ln K_{eq}$

Equating these two equations, we get:

$nfE^o_{cell}=RT\ln K_{eq}$

where,

n = number of electrons transferred = 2

F = Faraday's constant = 96500 C

$E^o_{cell}$ = standard electrode potential of the cell = 0.78 V

R = Gas constant = 8.314 J/K.mol

T = temperature of the reaction = $25^oC=[273+25]=298K$

$K_{eq}$ = equilibrium constant of the reaction = ?

Putting values in above equation, we get:

$2\times 96500\times 0.78=8.314\times 298\times \ln K_{eq}\\\\K_{eq}=2.44\times 10^{26}$

Hence, the $E^o_{cell}\text{ and }K_{eq}$ of the reaction is 0.78 V and $2.44\times 10^{26}$ respectively.

3 0

4 years ago

If 71.1 moles of CO2 react with H2, how many moles of H2O are produced

babymother [125]

Answer:

71.1 mol CO2 ( 1 mol CH4 / 1 mol CO2 ) = 71.1 mol CH4 produced

Explanation:

4 0

3 years ago

Read 2 more answers

Anne is trying to attract her metal pencil box with a magnet from the other side

Dima020 [189]

Answer:

The pencil box is too far away from the magnet to make it move.

Explanation:

The most likely scenario here is that the pencil box is too far away from the magnet to make it move.

A magnet has a force field around it which dictates the region where magnetic influences can be felt when a magnetic body is brought near it.

Outside the force field, a magnet has no effect on a magnetic body.

Since the magnet is not attracting or repelling the metallic box of pencils, they most be located outside the field of force of the magnet.
When they are within the force field, repulsion or attraction occurs and the field draws the metal to itself or repel.

Objects that are far away from a magnetic source will feel no effect of the force field of a bar magnet.

5 0

3 years ago