Question

3 Cu + 8HNO3 g 3 Cu(NO3)2 + 2 NO + 4 H2O

Answer 1

Considering the reaction stoichiometry, the amount of moles of NO that is produced when 27 moles of HNO₃ react is 6.75 moles.

Reaction stoichiometry

The balanced reaction is:

3 Cu + 8 HNO₃ → 3 Cu(NO₃)₂ + 2 NO + 4 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:  

• Cu: 3 moles
• HNO₃: 8 moles
• Cu(NO₃)₂: 3 moles
• NO: 2 moles
• H₂O: 4 moles

Amount of moles of NO produced

It is possible to determine the the amount of moles of NO produced by a rule of three: if by stoichiometry 8 moles of HNO₃ produce 2 moles of NO, if 27 moles of HNO₃ react how many moles of NO will be formed?

$amount of moles of NO=\frac{27 moles of HNO_{3} x 2 moles of NO}{8 moles of HNO_{3}}$

amount of moles of NO= 6.75 moles

In summary, the amount of moles of NO that is produced when 27 moles of HNO₃ react is 6.75 moles.

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