Consider, in ΔRPQ,
RP = R (Radius of larger circle)
PQ = r (radius of smaller circle)
We have to find, RQ, by Pythagoras theorem,
RP² = PQ²+RQ²
R² = r²+RQ²
RQ² = R²-r²
RQ = √(R²-r²
Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ
RS = 2√(R²-r²)
Answer:
B 5400
Step-by-step explanation:
first make two triangles using M , so there iwll be 90-45-45, and 30-60-90 then use the side rules of those special triangles
24% of 225 is 54, so you do 225+54=279 so 279 is the correct answer :)
Step-by-step explanation:
no they are not parallel
