D
is certainly wrong. You could extend the length of AD as far as you want and the two triangles (ABD and ACD) would still be congruent.
C
is wrong as well. The triangles might be similar, but they are more. They are congruent.
B
You don't have to prove that. It is given on the way the diagram is marked.
A
A is your answer. The two triangles are congruent by SAS
Answer:
D is the answer
Step-by-step explanation:
For a: g(x) = 1 when x = 1, for f(x) 1^2 - 2(1) + 2 = 1, a is true.
For b: Both functions do have all real numbers for their domain, b is true
For c: the y-intercept of g(x) is x = 0, for f(x), it is 0^2 - 2(0) + 2 = 2, c is true
For d: g(3) = 7, f(3) = 3^2 - 2(3) + 2 = 5, d is false.
I will check for the answer on that gimme a min
33,169
= 30,000+ 3,000+ 100+ 60+ 9.
The expanded form for 33,169 is 30,000+ 3,000+ 100+ 60+ 9~
OXY=90degree...and OYZ=90degree because the tangents supported in the circle are always 90
