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lesya [120]
3 years ago
10

Convert 6.90 x 10-3 km to nm3

Chemistry
1 answer:
marshall27 [118]3 years ago
5 0
I’m sorry I’m really not sure how to answer this but have to respond to have this app I hope you have a good day:)
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how many grams of solid silver nitrate would you need to prepare 200.0 mL of a 0.150 M AgNO3 solution
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0.150 M AgNO3 = x mol / 0.200 Liters
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Final answer = 5.097 grams, but if you want it in terms of sig figs then it is 5.09 grams.
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