There are 5 even numbers from 1 to 10.
The number of ways to draw all even numbers is 5!/(2!*3!) = 10
The number of ways to draw from the hat is 10!/(7!*3!) = 128
Therefore the probability is 10/128 = 5/64 or roughly 7.81%
While linear<span> equations are always straight, </span>nonlinear<span> equations often feature curves.</span>
Answer:
d= -16
Step-by-step explanation:
To answer this question you'll have to first simplify the equation to
0.2d+-1.2=0.3d+5-3+0.1d
then combining like terms you get
0.2d-1.2=(0.3d+0.1d)+(5+-3)
0.2d-1.2=0.4d+2
then subtract 0.4d from both sides leaving you with
-0.2d-1.2=2
then add 1.2 to both sides
-0.2d=3.2
after you divide both sides by -0.2
leaving you with the answer
D= -16
Answer:
Step-by-step explanation:
number of cards = 52
number of queen = 4
number of spades = 13
A) probability that the tenth card is a queen
drawn time (r) = 1
position of success(x) = 10th
p = 4/52
P( x,r,p) = 
p(10,1,4/52) = 9C0(4/52)^1 * (48/52)^9 = 0.0374
B) probability the twentieth card is a spade
x = 20
r = 1
p = 13 / 52
P(20,1,26/52) = 19C0(26/52)^1 * (26/52)^19 = 0.0010
c) The last five cards been spades
p(last five cards been spades )
p(48..52, 5, 13/52 ) = 47...52C4(13/52)^5 * (39/52)^48..52 - 5
The product of 8 and a number, rised to the power of two-thirds
