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N76 [4]
3 years ago
11

The Vertex is the part of a quadratic equation where the graph changes_________?

Mathematics
2 answers:
Georgia [21]3 years ago
8 0
I think it slopeeeeeeeeeeeeeeeeeeee
Alexus [3.1K]3 years ago
6 0
The answer is the slope. The vertex is the highest point in a quadratic equation and the slope gets affected by that because it describes the direction and the steepness of a line.
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HELP LOTS OF POINTS
Ray Of Light [21]

Answer:

16 units

Step-by-step explanation:

4+6+8=18

18-2=16

7 0
3 years ago
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Find the sales tax. Then find the total cost of the item. Sales Tax Selling Price Rate of Sales Tax Sales Tax $60.00 8% ? The sa
BlackZzzverrR [31]

Answer: Sales tax is $4.80 and the total cost is $64.80

Step-by-step explanation: Take the difference in the total before and after tax and divide by the price before tax.

To get $4.80, find the sales tax of $60.00 of 8%

We can use this formula: (selling price x sales tax rate)

The sales tax is: $4.80

To find the total cost, add 60.00 by the sales tax. ($4.80)

60.00 + 4.80 = $64.80

Therefore, these are your answers: $4.80 and $64.80

7 0
3 years ago
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A picture frame can hold a photograph that is 16 inches long and 12 inches wide. What is the area of the photo that fits the fra
yulyashka [42]

Answer: The area of the photo that fits the frame is 192 square inches.

Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:

Area of a rectangle (A) = Length x width

Replacing with the values given and solving for A (area):

A = 16 x 12 = 192 in2

The area of the photo that fits the frame is 192 square inches.

Feel free to ask for more if needed or if you did not understand something.

5 0
3 years ago
Simplify. 4 + 3 • (7 – 2) A. 19 B. 35 C. 47 D. 12
makvit [3.9K]
4 + 3 * (7 - 2)
4 + 3 * 5
4 + 15
19 <==
8 0
3 years ago
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Suppose that A = PDP-1 . Prove that det(A) = det(D)
daser333 [38]

Answer:

Check.

Step-by-step explanation:

To prove it we need to know that  for two matrices A and B we have that:

det(AB) = det(A)*det(B) and det(A^{-1}) = \frac{1}{det(A)}. Now:

A = PDP^{-1}

det(A) = det(PDP^{-1})

det(A) = det(P)*det(D)*det(P^{-1})

det(A) = det(P)*det(D)*\frac{1}{det(P)}

det(A) = det(P)*\frac{1}{det(P)}*det(D)

det(A) = det(D).

5 0
4 years ago
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