TheThe best approximation for the perimeter of polygon ABCDE is: C. 24.3 units.
<h3>Perimeter of polygon</h3>
Coordinate:
A=(-2,3)
B=(0,6)
C=(5,4)
D=(4,-1)
E=(-1,-2)
Distance AB=√(0+2)²+(6-3)²
Distance AB=√4+9
Distance AB=√13
Distance BC=√(5-0)²+(4-6)²
Distance BC=√25+4
Distance BC=√29
Distance CD=√(4-5)²+(-1-4)²
Distance CD=√1+25
Distance CD=√26
Distance DE=√(-1-4)²+(-2+1)²
Distance DE=√25+1
Distance DE=√26
Distance EA=√(-2+1)²+(3+2)²
Distance EA=√1+25
Distance EA=√26
Perimeter of pathogen ABCDE
=AB+BC+CD+DE+EA
=√13+√29+√26+√26+√26
=√13+√29+3√26
=24.2877 units
= 24.3 units (Approximately)
Therefore the correct option is C.
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Answer:
<em>95% confidence interval for the proportion of blocks that are sufficiently strong</em>
<em>(0.83913 , 1.02293)</em>
Step-by-step explanation:
<u><em>Step:-1</em></u>
Given that the sample size 'n' = 29 blocks
<em>Estimate proportion </em>

<u><em>Step:-2</em></u>
<em>95% confidence interval for the proportion of blocks that are sufficiently strong</em>


(0.93103 - 0.0919 , 0.93103 +0.0919)
(0.83913 , 1.02293)
<u><em>Final answer</em></u>:-
<em>95% confidence interval for the proportion of blocks that are sufficiently strong</em>
<em>(0.83913 , 1.02293)</em>
Answer:
Therefore 40 milliliter of 50% fungicide solution is required
Therfore 60 milliliter of 10% fungicide solution is required
Step-by-step explanation:
i) Let the 10% fungicide solution have x milliliter and the 50% fungicide solution have y milliliter.
ii) Therefore 10x + 50y = 26(x + y)
x + y = 100
iii) form the first equation in ii) we get
16 x = 24 y Therefore 
iv) substituting the value obtained in iii) in the second equation in ii) we get

Therefore y = 100 ÷ 2.5 = 40 milliliter
Therfore x = 100 - 40 = 60 milliliter