Which describes the substances that form covalent bonds?

Chemistry

1 answer:

enyata [817]3 years ago

8 0

The answer is C. Two Nonmetals

You might be interested in

What is 5 ounces in milliliters?

SIZIF [17.4K]

1 ounces ----------- 29.5735 mL
5 ounces ----------- ??

5 x 29.5735 / 1 => 147.868 mL

hope this helps!

6 0

3 years ago

What triggers the onset of estrus in most seasonal breeders

Anna11 [10]

Answer:

· Litter loss triggers estrus in a nonsocial seasonal breeder

Explanation:

6 0

3 years ago

What is the main function of mitochondria?

sweet [91]

Answer:

Mitochondria are membrane-bound cell organelles (mitochondrion, singular) that generate most of the chemical energy needed to power the cell's biochemical reactions. Chemical energy produced by the mitochondria is stored in a small molecule called adenosine triphosphate (ATP).

Explanation:

i did some research hope this help :)

7 0

4 years ago

List three ways in witch the water reaches the atmosphere

meriva

Three ways water reaches from earth to atmosphere are
1. direct evaporation from the water bodies like sea,river,oceans
2. moisture from the land(you must have seen land dries out)
3.moisture from the plant(small capillaries from the plants sucks water from land n goes to atmosphere in form of vapour from leaves)

7 0

3 years ago

How to balance lead and silver acetate yields lead (||) acetate and silver

arsen [322]

The given elements put into an equation using their symbols are as follows:
Pb + $AgC_{2}H_{3}O_{2}$ = $Pb(II){(C_{2}H_{3}O_{2})_2}$ + Ag

Since there are 2 Pb on the right side of the equation, you would change the coefficient of Pb on the left side to 2:
2Pb + $AgC_{2}H_{3}O_{2}$ = $Pb(II){(C_{2}H_{3}O_{2})_2}$ + Ag

Since there are 2 Acetate on the right side of the equation, you would change the coefficient of Silver Acetate on the left side to 2:
2Pb + $2AgC_{2}H_{3}O_{2}$ = $Pb(II){(C_{2}H_{3}O_{2})_2}$ + Ag

Now there are 2 Silver on the left side, so you change the coefficient of Silver on the right side to 2:
2Pb + $2AgC_{2}H_{3}O_{2}$ = $Pb(II){(C_{2}H_{3}O_{2})_2}$ + 2Ag

That is your final equation

The coefficients are 2 + 2 = 1 + 2

3 0

3 years ago