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tensa zangetsu [6.8K]
3 years ago
11

Which of the following statements regarding energy changes during a reaction are true?. 1) If the heat of reaction, ΔH, is negat

ive, the energy of the products is higher than the energy of the reactants, and the reaction is endothermic.2)Two or more atoms must collide, with proper orientation, with energy greater than or equal to the activation energy for a reaction to occur.3)When the activation energy is high, the reaction rate is fast.4) The energy of a collision between atoms or molecules must be greater than the activation energy (Ea) for bonds to be broken.
Chemistry
2 answers:
alexandr1967 [171]3 years ago
7 0

Answer:

2)Two or more atoms must collide, with proper orientation, with energy greater than or equal to the activation energy for a reaction to occur

Explanation:

Activation energy can be defined as the energy needed in order for a reaction to occur. Activation energy helps to also determine the rate of the reaction that is happening.

When the activation energy of a particular reaction is high, the rate or speed of that reaction tends to be slow while when the activation energy of a particular reaction is low, the rate or speed of that reaction in quite fast.

The Collision theory states that the collision of two or more reactants with the appropriate amount of energy (activation energy) and the proper or right orientation is what causes an effective chemical reaction to occur.

sergejj [24]3 years ago
4 0
2.<span>Two or more atoms must collide, with proper orientation, with energy greater than or equal to the activation energy for a reaction to occur</span>
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Enter your answer in the provided box. calculate the ph of a 0. 39 m ch3cooli solution. (ka for acetic acid = 1. 8 × 10−5. )
loris [4]

The pH of the solution is the negative logarithm of a proton or the hydrogen ion concentration. The pH of 0.39 M acetic acid solution (CH₃COONa) is 2.58.

<h3>What is pH?</h3>

The pH has been said to be the hydrogen ion concentration that can also be given by the pOH.

Given,

The acid dissociation constant Ka = 1.8 × 10⁻⁵

Concentration of acetic acid (C) = 0.39 M

The hydrogen ion concentration from Ka and molar concentration are calculated as:

H⁺ = √ Ka × C

= √1.8 × 10⁻⁵ × 0.39

= √0.00000702

= 0.0026

Now, pH from hydrogen ion is calculated as,

pH = - log [H⁺]

= - log [0.0026]

= 2.58

Therefore, the pH of acetic acid is 2.58.

Learn more about pH here:

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6 0
2 years ago
I will mark brainliest
Veronika [31]

I believe the answer is B??????????? Hope this helps

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5 0
3 years ago
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A solution contains only sucrose and water. If the mole fraction of sucrose is 0.0558, determine the molality of sucrose.
lora16 [44]

Answer:

The correct solution is "3.28 m".

Explanation:

According to the question,

Mol fraction of solvent,

= 0.0558

Molar mass of water,

= 18 g/mol

Mol of H₂O in 1000 g water,

= 55.55 mol

Now,

Let the mol of solute will be "x mol".

Total mol in solution will be "55.55 + x".

As we know,

⇒ The mol fraction of solvent = \frac{x}{55.55+x}

                                        0.0558=\frac{x}{55.55+x}

                                                x=0.0558[55.55+x]

                                                x=3.09969+0.0558x

                               x-0.0558x=3.09969

                                               x=\frac{3.09969}{0.9442}

                                                  =3.38 \ m

5 0
3 years ago
If 13.2 kg of Al 2 O 3 ( s ) , 50.4 kg of NaOH ( l ) , and 50.4 kg of HF ( g ) react completely, how many kilograms of cryolite
Elodia [21]

Answer : The mass of cryolite produced will be, 54.38 kg

Solution : Given,

Mass of Al_2O_3 = 13.2 kg  = 13200 g

Mass of NaOH = 50.4 kg  = 50400 g

Mass of HF = 50.4 kg  = 50400 g

Molar mass of Al_2O_3 = 101.9 g/mole

Molar mass of NaOH = 40 g/mole

Molar mass of HF = 20 g/mole

Molar mass of Na_3AlF_6 = 209.9 g/mole

First we have to calculate the moles of Al_2O_3,NaOH and HF.

\text{ Moles of }Al_2O_3=\frac{\text{ Mass of }Al_2O_3}{\text{ Molar mass of }Al_2O_3}=\frac{13200g}{101.9g/mole}=129.54moles

\text{ Moles of }NaOH=\frac{\text{ Mass of }NaOH}{\text{ Molar mass of }NaOH}=\frac{50400g}{40g/mole}=1260moles

\text{ Moles of }HF=\frac{\text{ Mass of }HF}{\text{ Molar mass of }HF}=\frac{50400g}{20g/mole}=2520moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

Al_2O_3+6NaOH+12HF\rightarrow 2Na_3AlF_6+9H_2O

From the balanced reaction we conclude that

The mole ratio of Al_2O_3,NaOH and HF is, 1 : 6 : 12

And, the ratio of given moles of Al_2O_3,NaOH and HF is, 129.54 : 1260 : 2520

From this we conclude that, NaOH,HF is an excess reagent because the given moles are greater than the required moles and Al_2O_3 is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of Na_3AlF_6

From the reaction, we conclude that

As, 1 mole of Al_2O_3 react to give 2 mole of Na_3AlF_6

So, 129.54 moles of Al_2O_3 react to give 129.54\times 2=259.08 moles of Na_3AlF_6

Now we have to calculate the mass of Na_3AlF_6

\text{ Mass of }Na_3AlF_6=\text{ Moles of }Na_3AlF_6\times \text{ Molar mass of }Na_3AlF_6

\text{ Mass of }Na_3AlF_6=(259.08moles)\times (209.9g/mole)=54380.892g=54.38kg

Thus, the mass of cryolite produced will be, 54.38 kg

5 0
3 years ago
how many moles of ammonium chloride are required for a complete reaction with 420 mol of calcium hydroxide
Oxana [17]

3 KOH + H3PO3 = K3PO4 + 3 H2O  

moles KOH = 26.5 g/56.1 g/mol=0.472  

moles K3PO4 = 0.472/3 =0.157

3 0
3 years ago
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