Answers are in an attached photo
Answer:
a. (3x^4 + 6 ) + (2x^2)
b. (X^3 ) + (-x -7)
c. (4.6x^4) + (-1.5x^2)
Step-by-step explanation:
For the first one, we have to write to polynomials, which equal 3x^4 + 2x^2 +6
One possible solution is (3x^4 + 6 ) + (2x^2)
For b, we can do,
(X^3 ) + (-x -7)
And finally for c, we can write,
(4.6x^4) + (-1.5x^2)
In the first series, the summation applies to the whole (2n+3) inside
the parentheses, so the 3 gets summed up 5 times.
But in the second one, the summation only applies to the 2n , so
the 3 is only added after the summation is finished.
The difference between five 3s the first time and one 3 the second time
is your 12 .