9514 1404 393
Answer:
see below for the graph
Step-by-step explanation:
We can specify the location of the minimum and the axis of symmetry using the vertex form of the quadratic equation:
y = a(x -h)² +k . . . . . . . vertex (h, k); scale factor 'a'
We can put the given values into the equation to see what 'a' needs to be to make the function have the desired y-intercept.
-3 = a(0 -(-2))² +(-5)
2 = 4a . . . . add 5 and simplify
a = 1/2 . . . . divide by 4
The equation for the desired function can be ...
y = 1/2(x +2)² -5
