Answer: The first one: 2 square roots of 3
Step-by-step explanation:
4/2 would give you the base= 2
2x the square root of 3 would give you the height, or altitude.
2 square roots of 3
Answer:
1.101 1.1012 1.11 1.1
Step-by-step explanation:
We write the equation in terms of dy/dx,
<span>y'(x)=sqrt (2y(x)+18)</span>
dy/dx = sqrt(2y + 18)
dy/dx = sqrt(2) ( sqrt(y + 9))
Separating the variables in the equation, we will have:
<span>1/sqrt(y + 9) dy= sqrt(2) dx </span>
Integrating both sides, we will obtain
<span>2sqrt(y+9) = x(sqrt(2)) + c </span>
<span>where c is a constant and can be determined by using the boundary condition given </span>
<span>y(5)=9 : x = 5, y = 9
</span><span>sqrt(9+9) = 5/sqrt(2) + C </span>
<span>C = sqrt(18) - 5/sqrt(2) = sqrt(2) / 2</span>
Substituting to the original equation,
sqrt(y+9) = x/sqrt(2) + sqrt(2) / 2
<span>sqrt(y+9) = (2x + 2) / 2sqrt(2)
</span>
Squaring both sides, we will obtain,
<span>y + 9 = ((2x+2)^2) / 8</span>
y = ((2x+2)^2) / 8 - 9
Try this solution:
1. In order to built the line required in the condition it need to determine its equation.
Using the coordinates of point B (5;2), if to substitute them into the given equation: 2=-3*5+b, ⇒ b=17. It means, that the equation of the line required in the condition is y= -3x+17.
2. The graph is in the attachment; point (0;17) is the intersection point of Y-axis and the line.