Answer:
buss stop 2
Step-by-step explanation:
Problem
For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground
Solution
We know that the x coordinate of a quadratic function is given by:
Vx= -b/2a
And the y coordinate correspond to the maximum value of y.
Then the best options are C and D but the best option is:
D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a
The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.
The smallest possible value of z is the denominator of the reduced fraction x/y. We note the prime factors of the members of set y are
... 2², 7, 2³, 3²
so if there are any even members of set x, the fraction can be reduced to something divided by 2. The number 6 in set x is even, so we have
... 6z/4 = 6·2/4 = 3 (an integer) when z=2
The lowest possible value of z is ...
... B) 2
