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2 years ago

5

Please solve very urgent

2 answers:

Snezhnost [94]2 years ago

3 0

Step-by-step explanation:

Can't see the picture very So can you updated

nlexa [21]2 years ago

3 0

ANSWER: X = 45
First, you have to set up the equation.
If the area of the square is 9, and one side is 3 square units, then the other side must also be 3 units because 3X3=9.
When finding the value of a variable, you ALWAYS want to get the variable alone on one side.
So now, you take the equation, 1/9x-2 and make is equivalent to 3.
1/9x-2=3
Now, to simplify, you add to to undo the -2, and add 2 to the 3
1/9x-2(+2)=3+2
So now the equation is 1/9x=5
To undo a fraction, think of it as a division problem. To undo a division problem, you must multiply the fraction by the denominator.
1/9x(9)=5(9)
5X9 is 45
So the answer is X=45
And is you want to check it:
1/9(45)-2=3
1/9X45 is 45/9 or 5
5-2=3
3=3
The answer is X=45

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Find the range of f(x)=-2x + 6 for the domain {-1, 3, 7, 9}

Blizzard [7]

Answer:

range {4, 12, 20, 24}

Step-by-step explanation:

Plug each of the numbers in for x and solve for y

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2 years ago

A rectangular cracker has a length of 5 centimeters and an area f 20 square centimeters. Find its perimeter.

iren [92.7K]

Answer:

18cm

Step-by-step explanation:

We have the length of the rectangle but we need to find the width which we'll call w. Area is a, l is length.

a = l * w

20 = 5 * w

divide both sides by 5 to cancel the multiplication by 5 on the right side

4 = w

The rectangle is going to have two sides that are the length of l, and two sides that are the the length of w. We're looking for the perimiter p.

p = 2l + 2w

p = (2 * 5) + (2 * 4)

p = 18

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2 years ago

Find the exact value of cos(a+b) if cos a=-1/3 and cos b=-1/4 if the terminal side if a lies in quadrant 3 and the terminal side

maria [59]

Answer:

cos(a + b) = $\frac{1}{12}(1-2\sqrt{30})$

Step-by-step explanation:

cos(a + b) = cos(a).cos(b) - sin(a).sin(b) [Identity]

cos(a) = $-\frac{1}{3}$

cos(b) = $-\frac{1}{4}$

Since, terminal side of angle 'a' lies in quadrant 3, sine of angle 'a' will be negative.

sin(a) = $-\sqrt{1-(-\frac{1}{3})^2}$ [Since, sin(a) = $\sqrt{(1-\text{cos}^2a)}$ ]

= $-\sqrt{\frac{8}{9}}$

= $-\frac{2\sqrt{2}}{3}$

Similarly, terminal side of angle 'b' lies in quadrant 2, sine of angle 'b' will be negative.

sin(b) = $-\sqrt{1-(-\frac{1}{4})^2}$

= $-\sqrt{\frac{15}{16}}$

= $-\frac{\sqrt{15}}{4}$

By substituting these values in the identity,

cos(a + b) = $(-\frac{1}{3})(-\frac{1}{4})-(-\frac{2\sqrt{2}}{3})(-\frac{\sqrt{15}}{4})$

= $\frac{1}{12}-\frac{\sqrt{120}}{12}$

= $\frac{1}{12}(1-\sqrt{120})$

= $\frac{1}{12}(1-2\sqrt{30})$

Therefore, cos(a + b) = $\frac{1}{12}(1-2\sqrt{30})$

5 0

3 years ago

I need Help fast asap thank you

Jobisdone [24]

Answer:

1.25

Step-by-step explanation:

Because they are equal triangles, all of their sides are equal

so, lets take one side of each triangle (4, 5)

the law:

the scale factor = the larger side ÷ the smaller side

x = 5 ÷ 4

x = 1.25

For checking:

the larger side = the smaller side × the scale factor

Y = 4 × 1.25

Y = 5

8 0

2 years ago

Alex must read at least 500 pages of his book this month. He has already read 260 pages. If he reads 30 pages a day, what is the

slamgirl [31]

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2 years ago