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Leokris [45]
3 years ago
15

- Save & Exit Certify

Mathematics
1 answer:
zavuch27 [327]3 years ago
3 0

Answer:

(-3, -8)

Step-by-step explanation:

2x-2y=10

ordered pair given x=-3

then 2 (-3) - 2y=10

-6-2y=10

-2y=16

y=-8

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Help please <br><br> Arrange four 2's to produce 5
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Answer:

See below

Step-by-step explanation:

Produce 5 using four 2's:

<u>Solution 1</u>

  • 2*2 + 2/2 =
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<u>Solution 2</u>

  • 2+2 + 2/2 =
  • 4+ 1=
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<u>Solution 3</u>

  • 2² + 2/2 =
  • 4 + 1 =
  • 5
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What is 82.53 divided by 5
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F(x) = x2 – 3x – 2 is shifted 4 units left. The result is g(x). What is g(x)?
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\bf \begin{array}{llll}&#10;&#10;&#10;\bullet \textit{ vertical shift by }{{  D}}\\&#10;\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\&#10;\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\&#10;\bullet \textit{ period of }\frac{2\pi }{{{  B}}}&#10;\end{array}

now... your expression is not in vertex form, that's ok... to do a horizontal shift to the left by 4 units, we can simply, add the C  and B component to the "x" variable, C=4, B =1, that way the horizontal shift of C/B or 4/1 is just +4, giving us a horizontal shift to the left

\bf f(x)=x^2-3x-2\impliedby \textit{let's change that for }f(1x+4)&#10;\\\\\\&#10;f(1x+4)=(1x+4)^2-3(1x+4)-2&#10;\\\\\\&#10;f(x+4)=x^2+8x+16-3x-12-2&#10;\\\\\\&#10;f(x+4)=x^2-5x+2\impliedby g(x)


8 0
3 years ago
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Custom drapes are being fitted for a large circular
qwelly [4]
The diameter is 17ft
5 0
3 years ago
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What are the coordinates of the vertex of the parabola represent by the equation y=-5x^2+30x-25
Jobisdone [24]

Answer:

The coordinate of the  vertex of the parabola is (h,k) =  (3,20)

Step-by-step explanation:

The given equation of the parabola is y=-5x^2+30x-25

Now, the General Parabolic Equation is of the form:

y = a (x-h)^2 + k, then the vertex is the point (h, k).

Now, to covert the given equation in the standard form:

y=-5x^2+30x-25   = -5(x^2  -6x   + 5)

Using the COMPLETE THE SQUARE METHOD,

-5(x^2  -6x   + 5)  = -5(x^2  -6x  +  (3)^2 +  5  - (3)^2)\\\implies -5(((x^2  -6x +(3)^2)  + 5 - 9)\\= -5((x-3)^3 -4)\\= -5(x-3)^2 + 20

ory = -5(x-3)^2 + 20

⇒The general formed equation of the given parabola is

y  = -5(x-3)^2 + 20

Comparing this with general form, we get

h = 3, k = 20

Hence, the coordinate of the  vertex of the parabola is (h,k) =  (3,20)

5 0
4 years ago
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