Angle 1 = 40°
Angle 2 = x°
Angle 3 = ( x + 28 )°
The value of x.
✅
We know that,
➪ ∠ 1 + ∠ 2 + ∠ 3 = 180°
➪ 40 + x° + x° + 28° = 180°
➪ 2x° + 68° = 180°
➪ 2x° = 180° - 68°
➪ x° =
➪ x° = 56°
∠ 1 + ∠ 2 + ∠ 3 = 180°
✒ 40° + 56° + 56° + 28° = 180°
✒ 180° = 180°
✒ L. H. S. = R. H. S.
Answer:
Step-by-step explanation:
so when the height is zero, that's when the rocket hits the ground. The equation will have two zeros, but one would be for a negative time, or before the rocket is launched. so we only one the one after the rocket is launched.
use the quadratic formula to solve for x ( which is time)
-124 +- sqrt [ - 4*(-16)*(127) ] / 2 (-16)
-124 +- sqrt [15376 + 8128 ] / -32
-124 +- sqrt [23504 ] / -32
-124 +- 153.310 / -32
if we take the positive part it will become the negative time so skip that one try the negative part 1st
-124 - 153.310 / -32
-277.310 / -32
8.6659 seconds to hit the ground. ( time of flight) aka TOF
8.67 seconds ( rounded to nearest 100th)
