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Olin [163]
3 years ago
14

pA submarine submerged at a depth of -35.25 meters dives an additional 8.5 meters. What is the new depth of the submarine?

Mathematics
1 answer:
finlep [7]3 years ago
5 0
-43.75. -35.25 minus 8.5 is -43.75
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1)A System of equations is shown below . What is the solution to the system of equations? 5x+2y=-15 2x-2y=-6
meriva

Answer:

x= -3 and y= 0

Step-by-step explanation:

5x+2y=-15

<u>2x-2y=-6     </u>

<u>7x        =-21</u>

x= -3

Putting value of x in equation 1  

5(-3) +2y=-15

-15+2y= -15

2y= 0

y= 0

This can be solved with the help of matrices

In matrix form the above equations can be written in the form

\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right]  \left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]

Let

\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right] = A  \left[\begin{array}{ccc}x\\y\\\end{array}\right]  = X  and  \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]= B

Then AX= B

or X= A⁻¹ B

where  A⁻¹= adj A/ ║A║   where mod A≠ 0

adj A=  \left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]

║A║= ( 5*-2- 2*2)= -10-4= -14≠0

X= A⁻¹ B

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]    =- 1/14  \left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]   \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]    =- 1/14     \left[\begin{array}{ccc}-2*-15&+ -2*-6\\-2*-15&+ 5*-6\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]  =- 1/14 \left[\begin{array}{ccc} 30&+12\\30&+-30\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]  =- 1/14 \left[\begin{array}{ccc}42\\0\\\end{array}\right]

\left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-42/14\\0/-14\\\end{array}\right]

\left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-3\\0\\\end{array}\right]

From here x= -3 and y= 0

Solution Set = [(-3,0)]

3 0
3 years ago
What is the surface area of the prism?
kow [346]
The\ surface\ area:A_s=2B+(S_1+S_2+S_3)\cdot H\\B=\frac{12\cdot5}{2}=\frac{60}{2}=\boxed{30\ (yd^2)}\\\\S_1=5yd;\ S_2=12yd;\ S_3=13yd;\ h=8yd\\\\therefore\\\\A_s=2\cdot30+(5+12+13)\cdot8=60+30\cdot8=60+240=\boxed{300\ (yd^2)}Volume\ of\ the\ prism:V=B\cdot H\\\\B\ (base)\ it's\ a\ right\ triangle:B=\frac{12\cdot5}{2}=\frac{60}{2}=\boxed{30\ (yd^2)}\\\\H=8yd\\\\therefore\\\\V=30\cdot8=\boxed{240\ (yd^2)}\leftarrow\boxed{C}
8 0
3 years ago
Read 2 more answers
Is 12.56 bigger than 125.6
VARVARA [1.3K]
No it's smaller. 12.56 is much less than 125.6.

5 0
3 years ago
Which expression has the same value as 37.4 - 54.9?
GrogVix [38]

Answer:

D

Step-by-step explanation:

In the original expression =  37.4 - 54.9 = -17.5

So, we have to solve all the equations but 1 of them has to equal to -17.5

A) -54.9 + (-37.4) = -92.3

   Remove parentheses

   = -54.9 - 37.4

Subtract the numbers

    -92.3

B) 54.9 - 37.4 = 17.5

Since 54.9 is greater than 37.4 just subtract normally

 4   14

  5  4.   9                < ------- Line up the decimal points like this

-  3  7.   4                <---------  Subtract the decimals

-----------------

   1   7   .    5       <---------- This is the final answer to B.                    

 

C)  37.4 - (- 54.9) = 92.3

   Change the sign to addition

        =37.4 + 54.9

  Add the numbers normally

  54.9

+ 37. 4

--------------

  92.3

D)  37.4 + (-54.9) = -17.5

   Change the sign to subtraction

      =    37.4 - 54.9

Subtract them normally (but as you can see you are subtracting a smaller number from a larger number so heres a trick that you can use switch the equation by putting the larger number in first like this....)

54.9 - 37.4 = 17.5 (REMEMBER the answer is not 17.5 because the original equation of D is reversed  37.4 - 54.9 so in this case your answer should be

- 17.5)

37.4 - 54.9 = -17.5

Your final answer is D because it matches 37.4 - 54.9.

Hope this helps!

3 0
3 years ago
Read 2 more answers
How do you substitute the equation x=y-1
umka2103 [35]
If you need to substitute the equation x = y - 1.
If you have another equation, then you would plug in y - 1 into the x value of the equation you would need to substitute into. 

Hope this helps
7 0
3 years ago
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