Please read the attached file
Let x and y represent the numbers of gallons used by the 40 mpg and 35 mpg cars, respectively.
.. x +y = 40 . . . . . . . . . . .total consumption is 40 gallons
.. 40x +35y = 1525 . . . . total miles driven = 1525
Multiply the first equation by 40 and subtract the second.
.. 40(x +y) -(40x +35y) = 40(40) -(1525)
.. 5y = 75
.. y = 15
.. x = 40 -15 = 25
The 40 mpg car consumed 25 gallons.
The 35 mpg car consumed 15 gallons.
Answer:
a.) The sum of the weights of the two in insects is 0.0031 grams. (0.0031 grams)
b.) The fly is 0.0013 grams heavier than the gnat. (0.0013 grams)
Step-by-step explanation:
2.2 * 10^-3 = 2.2 * 1/1000 which is 2.2/1000.
9 * 10^-4 = 9 * 1/10000 = 9/10000
To add 9/10000 to 2.2/1000 we have to find the common denominator, which will be 10000.
So we do:
2.2/1000 * 10/10 = 22/10000
9/10000 + 22/10000 = 31/10000 = 0.0031.
The sum of the weights of the two in insects is 0.0031 grams.
To find how much heavier the fly is than the gnat we do:
22/10000 - 9/10000 = 13/10000 = 0.0013
The fly is 0.0013 grams heavier than the gnat.
Answer:
6/15 divided by 6
Step-by-step explanation:
Given :
On the first day of ticket sales the school sold 10 senior tickets and 1 child ticket for a total of $85 .
The school took in $75 on the second day by selling 5 senior citizens tickets and 7 child tickets.
To Find :
The price of a senior ticket and the price of a child ticket.
Solution :
Let, price of senior ticket and child ticket is x and y respectively.
Mathematical equation of condition 1 :
10x + y = 85 ...1)
Mathematical equation of condition 2 :
5x + 7y = 75 ...2)
Solving equation 1 and 2, we get :
2(2) - (1) :
2( 5x + 7y - 75 ) - ( 10x +y - 85 ) = 0
10x + 14y - 150 - 10x - y + 85 = 0
13y = 65
y = 5
10x - 5 = 85
x = 8
Therefore, price of a senior ticket and the price of a child ticket $8 and $5.
Hence, this is the required solution.
