Given :
Center of sphere , C( 1 , -1 , 6 ) .
To Find :
Find equations of the spheres with center (1, −1, 6) that touch the following planes.a) xy-plane b) yz-plane c) xz-plane .
Solution :
a)
Distance of the point from xy-plane is :
d = 6 units .
So , equation of circle with center C and radius 6 units is :
b)
Distance of point from yz-plane is :
d = 1 unit .
So , equation of circle with center C and radius 1 units is :
c)
Distance of point from xz-plane is :
d = 1 unit .
So , equation of circle with center C and radius 1 units is :
Hence , this is the required solution .
I hope everythink is clearly :) If not just ask :)
answer for your question is starting when x^2-14x-95=0. Just Ignore this above this.
Answer: 
.
Step-by-step explanation:
It is given that Point A is at (-5, -4) and point B at (-3, 3).
We need to find the coordinates of the point which is 3/4 of the way from A to B.
Let the required point be P.
It means, point P divides segment AB in 3:1.
Section formula: If a point divides a line segment in m:n, then
Using section formula, we get
Therefore, the required point is .
Answer:
95% confidence interval for the mean μ is (6,14)
The Population mean μ lies between ( 6, 14 )
Step-by-step explanation:
<u><em>Explanation</em></u>:-
Given random sample 'n' = 1200
95% confidence interval for the mean μ is determined by
Level of significance = 95% 0r 0.05
Z₀.₀₅ = 1.96
= 10 ± 4
Mean of the small sample = 10
95% of confidence intervals are
( 10 ±4 )
( 10 -4 , 10+4)
( 6 , 14 )
95% confidence interval for the mean μ lies between ( 6, 14 )
Answer:
second option is the right answer
plz mark brainliest✌️✌️
