Answer:
y=(8/9)x + 4 and 2/3
Step-by-step explanation:
the slope of this line:
change in y/change in x
change in y=6-(-2)=8
change in x=-6-3=-9
change in y/change in x= 8/9
8/9 is the slope, so you plug it in for m in the standard form equation. You then use one point's x and y values to substitute for x and y in the equation, and solve for b, which is the y intercept
y=mx+b
y=(8/9)x+b
-2=(8/9)*3+b
-2=8/3+b
-4 and 2/3=b
*Hint: The formula for the lateral surface area of a right cone is LA= Πrs
All we have to do is plug in and solve.
LA= Π(3)(5)
LA = 15Π
LA = 47.1238898
The lateral surface area is around 48 inches.
Answer:
A) g(t) = - 16*t² + 80*t
B) domain is ( 0 ≤ t ≤ 5 )
Step-by-step explanation:
A) for the model rocket
h = 0 and v = 80 feet/sec
Then the equation g(t) = -16*t² + v*t + h
became
g(t) = - 16*t² + 80*t + 0 g(t) = - 16*t² + 80*t
B) The equation g(t) = - 16*t² + 80*t is defined for all real numbers then the domain interval for t is ( -∞ , ∞ ). Now in our case, a model rocket was launched is not possible to get negative values for g(t) then the biggest value for t = 5 from
-16*t² + 80*t ≥ 0
-16*t ≥ -80 16*t ≤ 80
t ≤ 5
And the domain is ( 0 ≤ t ≤ 5 )
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<span>The absolute value inequality of a length of 36.80 mm with a tolerance of 0.05 mm</span> is given by |x - 36.80| < 0.05
and
The compound inequality of a length of 36.80 mm with a tolerance of 0.05 mm is obtained as follows:
|x - 36.80| < 0.05
-0.05 < x - 36.80 < 0.05
-0.05 + 36.80 < x < 0.05 + 36.80
36.75 < x < 36.85.
