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Ne4ueva [31]
3 years ago
15

Sammy has 20 cookies what is 20 rounded to the nearest ten

Mathematics
2 answers:
Kobotan [32]3 years ago
5 0
If I'm understanding this correctly 20 rounded to the nearest ten would be 20
xeze [42]3 years ago
4 0
20 rounded to the nearest ten is still 20
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elise gets a free tax allowance of $6000 and pays tax at 25% on the next $20 000. she pays tax at a raye of 30% on the rest. if
Likurg_2 [28]

Answer:

c

Step-by-step explanation:

i know because im not g.a.y like u guys

4 0
3 years ago
Wendall designs a tower with a height in feet that can be represented by the function T(x) = 9(x + 6.9), where x is the height o
Vinil7 [7]

Answer:

G(T(x)) = 27(x + 6.9)

Step-by-step explanation:

Given

T(x) = 9(x + 6.9)

G(x) = 3x

Required [Missing from the question]

G(T(x))

We have:

G(x) = 3x

This implies that:

G(T(x)) = 3(T(x))

Substitute: T(x) = 9(x + 6.9)

G(T(x)) = 3[9(x + 6.9)]

Open bracket

G(T(x)) = 27(x + 6.9)

6 0
3 years ago
Help. Please. Thank You.
GenaCL600 [577]

Answer:

(A)\ a=-6;b=4\\\\ (B)\ a=6;b=-4

Step-by-step explanation:

The equation of the line in Slope-Intercept form is:

y=mx+c

Where "m" is the slope and "c" is the y-intercept.

By definition:

1. If the lines of the System of equations are parallel (whrn they have the same slope), the system has No solutions.

2. If the they are the same exact line, the System of equations has Infinite solutions.

(A) Let's solve for "y" from the first equation:

3x-2y=-1\\\\-2y=-3x-1\\\\y=\frac{3}{2}x+\frac{1}{2}

You can notice that:

m=\frac{3}{2}\\\\c=\frac{1}{2}

In order make that the System has No solutions, the slopes must be the same, but the y-intercept must not. Then, the values of "a" and "b" can be:

a=-6\\\\b=4

Substituting those values into the second equation and solving for "y", you get:

-6x+4y=-2\\\\4y=6x-2\\\\y=\frac{6}{4}x-{2}{4}\\\\y=\frac{3}{2}x-\frac{1}{2}

You can idenfity that:

m=\frac{3}{2}\\\\c=-\frac{1}{2}

Therefore, they are parallel.

(B) In order make that the System has Infinite solutions, the slopes and the y-intercepts of both equations must be the same. Then, the values of "a" and "b" can be:

a=6\\\\b=-4

If you substitute those values into the second equation and then you solve for "y", you get:

6x+(-4y)=-2\\\\-4y=-6x-2\\\\y=\frac{-6}{-4}x-\frac{2}{-4}\\\\y=\frac{3}{2}x+\frac{1}{2}

You can identify that:

m=\frac{3}{2}\\\\b=\frac{1}{2}

Therefore, they are the same line.

3 0
4 years ago
Please help out with this problem I have. Brainliest answer will be given
Viktor [21]
C I think because the lines intercept at a common point
6 0
3 years ago
Find an explicit rule for the nth term of a geometric sequence where the second and fifth terms are -6 and 162, respectively. Pl
kicyunya [14]
Hello,

u_{0} =a\\
 u_{1} =a*r\\
 u_{2} =a*r^{2}=-6\\
 u_{3} =a*r^{3}\\
 u_{4} =a*r^{4}\\
 u_{5} =a*r^{5}=162\\
....\\
\boxed{ u_{n} =a*r^{n}} \\

\dfrac{ 162}{-6} = \dfrac{ u_{5} }{ u_{3}} = \dfrac{ a*r^{5}}{ a*r^{2}} =r^3= -27\\
==\ \textgreater \  r=-3\\

 u_{2} =a*r^{2}=-6=a*(-3)^2 \ ==\ \textgreater \  a=-\frac{6}{9} =-\frac{2}{3}\\


\boxed{ u_{n} =-\frac{2}{3}*(-3)^{n}=(-1)^{n+1}*2*3^{n-1}} \\


8 0
4 years ago
Read 2 more answers
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