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2 years ago

A shop sells packets of envelopes.

Mathematics

1 answer:

Ivanshal [37]2 years ago

5 0

9514 1404 393

Answer:

5x +20y = T

Step-by-step explanation:

There are 5 envelopes in each of x small packets, for a total of 5x envelopes in small packets.

There are 20 envelopes in each of y large packets, for a total of 20y envelopes in large packets.

The total number envelopes is then ...

T = 5x +20y

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Plz plz plz help me its for math

skad [1K]

Letter C is the correct answer

7 0

2 years ago

A spinning giant star of initial radius R1 and angular speed ω1 suddenly collapses radially inward reaching a new radius R2 = 0.

tiny-mole [99]

Answer:

K1/K2=4

Step-by-step explanation:

The kinetic energy of a rotating sphere is given by:

$K=\frac{I*\omega^{2} }{2}$

The moment of inertia of a solid sphere is given by

$I=\frac{2MR^{2} }{5}$

The initial kinetic energy is therefore

$K_1=\frac{2MR^{2}*\omega^{2} }{10}$

$K_1=\frac{MR_1^{2}*\omega^{2} }{5}$

The final kinetic energy is given by

$K_2=\frac{MR_2^{2}*\omega^{2} }{5}$

Therefore the relation K1/K2 if R2 = 0.5R1

$\frac{K_1}{K_2} =\frac{5M(R_1)^{2}*\omega^{2} }{5*M(0.5R_1)^{2} \omega^{2}}$

The text says nothing about the final angular velocity just the collapse of the collapse of the radius

$\frac{K_1}{K_2} =\frac{1 }{(0.5)^{2} }=4$

3 0

2 years ago

Order of operations how do you solve 10/5*(7-2+4^2)

kvv77 [185]

10/5 =2
7-2+4^2 =5+16=21
2*21=42

3 0

2 years ago

Two possible solutions of √11-2x=√x^2+4x+4 are –7 and 1. Which statement is true? A) Only x = –7 is an extraneous solution.

11111nata11111 [884]

Answer:

Option D)Neither solution is extraneous.

Step-by-step explanation:

we have

$\sqrt{11-2x}=\sqrt{x^{2}+4x+4}$

we know that

two possible solutions are x=-7 and x=1

Verify each solution

Substitute each value of x in the expression above and interpret the results

1) For x=-7

$\sqrt{11-2(-7)}=\sqrt{-7^{2}+4(-7)+4}$

$\sqrt{25}=\sqrt{25}$

$5=5$ ----> is true

therefore

x=-7 is not a an extraneous solution

2) For x=1

$\sqrt{11-2(1)}=\sqrt{1^{2}+4(1)+4}$

$\sqrt{9}=\sqrt{9}$

$3=3$ ----> is true

therefore

x=1 is not a an extraneous solution

therefore

Neither solution is extraneous

7 0

2 years ago

Read 2 more answers

Which of the following is NOT equivalent to 240/300

Lyrx [107]

Two fractions are said to be equivalent if both the numerator and the numerator of one fraction can be obtained by multiplying or dividing the numerat.or and denominator of the other fraction by a single factor.

Dividing the numerator and denominator of 240/300 by 5 gives 48/60
Dividing the numerator and denominator of 240/300 by 60 gives 4/5
Dividing the numerator and denominator of 240/300 by 10 gives 24/30

Whereas dividing 300 by 2 gives 150 dividing 240 by 2 will not give 122. so 122/150 is not equivalent to 240/300.

7 0

2 years ago