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nadya68 [22]
3 years ago
6

HELP I need the know if it's going across the y or going across the x don't send no FILE ONLY ANSWER IF YOU REALLY KNOW question

3, 5 is what I need help on btw !!

Mathematics
2 answers:
Alika [10]3 years ago
7 0

Answer:

i think 3 is reflected across the x and 5 is reflected across the y axis

spayn [35]3 years ago
3 0

Answer:

Step-by-step explanation:

Question 3 Reflects over x acis

Question 5 reflects over y axis

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If g(x)=x^2+5, find g(3). Pls answer
guapka [62]

Answer:

14

Step-by-step explanation:

{3}^{2}  + 5 = 14

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3 0
3 years ago
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I need help please
guajiro [1.7K]

Answer:

distance = 10.6

Step-by-step explanation:

A's coords are (5, 6)

D's coords are (-2, -2)

So the total horizontal distance between A and D is:

5 + 2 = 7

...and the total vertical distance is:

6 + 2 = 8

Now use Pythagorean Theorem:

7^2 + 8^2 = distance^2

distance^2 = 49 + 64 = 113

distance = squareroot of 113

distance = 10.6

3 0
3 years ago
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Omar runs 3 miles everyday. He runs a mile in 4 minutes 30 seconds. How many miles did he run in the month of February?​
Vlad [161]

Answer:

so he ran 84 miles and if you need 378.

Step-by-step explanation:

3*28=84miles

and then 84*4.5=378

8 0
3 years ago
Please help me quick
snow_tiger [21]
I believe it should be twelve (Brainliest please)
6 0
3 years ago
A study of women’s weights found that a randomly selected sample of 234 women had a mean weight of 157.3 lb. Assuming that the p
Scilla [17]

Answer:

157.3-1.96\frac{15.6}{\sqrt{234}}=155.301    

157.3+1.96\frac{15.6}{\sqrt{234}}=159.299    

So on this case the 95% confidence interval would be given by (155.301;159.299)    

And the best option would be:

B. (155.3, 159,3)

Step-by-step explanation:

Information given

\bar X=157.3 represent the sample mean

\mu population mean (variable of interest)

\sigma =15.6 represent the population standard deviation

n=234 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The Confidence level is is 0.95 or 95%, the significance is \alpha=0.05 and \alpha/2 =0.025, the critical value for this case would be z_{\alpha/2}=1.96

And replacing we got:

157.3-1.96\frac{15.6}{\sqrt{234}}=155.301    

157.3+1.96\frac{15.6}{\sqrt{234}}=159.299    

So on this case the 95% confidence interval would be given by (155.301;159.299)    

And the best option would be:

B. (155.3, 159,3)

5 0
4 years ago
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