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ExtremeBDS [4]
3 years ago
13

with the square root of negative 1 in the numerator (the top) and eight in the demominator (on bottom) what is the answer

Mathematics
1 answer:
AleksAgata [21]3 years ago
6 0
-1^2/8 = 1/8 is the answer
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(3ab-3a-8)-(-4ab-8) find the difference
sdas [7]
3ab - 3a - 8 + 4ab + 8
7ab -3a
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3 years ago
I need answers quick thanks
Tema [17]
B :) open circle means inequality and it needs to be at least 3 so the line has to increase, meaning the arrow is going right.
8 0
2 years ago
A simple dart target has two concentric circles. The larger circle has a radius of 4. The smaller circle has a radius of 2. The
Natali5045456 [20]

Answer:

3 times more.

Step-by-step explanation:

The odds of landing a dart in any of the circles correspond to the surface area of the circle.

Calculate the surface area of both circles:

The formula for the area of a circle is \pi r^{2}.

  • inner circle: A=\pi 2^{2}=12.566
  • for the outer circle, use the formula then subtract the value of the inner circle, to find the remaining area: A=(\pi 4^{2} )-12.566=37.699

Calculating greater chance:

Divide the larger area by the smaller area:

37.699/12.566 = 3

That means that the area of the outer circle is 3 times larger, making it 3 times more likely to hit the outer circle. Therefore the points for hitting the inner circle should be 3 times more.

7 0
3 years ago
Bill needs to build a rectangular sheep pen
Ymorist [56]

Perimeter = 24m

Cost of half metre(1/2m) = €1.20

Cost of one metre = €2.40

Cost of fencing = 24 × 2.40 = €57.60

HOPE THIS WILL HELP YOU

7 0
3 years ago
Read 2 more answers
Rollie was succesful in losing weight he had a goal weight in mind he went on a diet for three months each month he would lose o
Llana [10]
Let's say that in the beginning he weighted x and at the end he weighted x-y, y being the number of kg he wanted to loose.

first month he lost
y/3

then he lost:  
(y-y/3)/3
this is
(2/3y)/3=2/9y
explanation: ((y-y/3) is what he still needed to loose: y minus what he lost already

and then he lost
 (y-2/9y-1/3y)/3+3 (the +3 is his additional 3 pounts)
 (y-2/9y-1/3y)/3-3=(7/9y-3/9y)/3+3=4/27y+3

it's not just y/3 because each month he lost one third of what the needed to loose at the current time, not in totatl

and  the weight at the end of the 3 months was still x-y+3, 3 pounds over his goal weight!


so:  x -y/3-2/9y-4/27y-3=x-y+3

we can subtract x from both sides:
-y/3-2/9y-4/27y-3=-y+3
add everything up:

-19/27y=-y+6

which means
-19/27y=-y+6

y-6=19/27y

8/27y=6
4/27y=3
y=20.25

so... that's how much he wanted to loose, but he lost 3 less than that, so 23.25

ps. i hope I didn't make a mistake in counting, let me know if i did. In any case you know HOW to solve it now, try to do the calculations yourself to see if they're correct!










5 0
3 years ago
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