All categories

3 years ago

with the square root of negative 1 in the numerator (the top) and eight in the demominator (on bottom) what is the answer

Mathematics

1 answer:

AleksAgata [21]3 years ago

6 0

-1^2/8 = 1/8 is the answer

You might be interested in

Order the numbers from least to greatest. 3 63/80 , 3 1/5 , 3 11/20

gregori [183]

Let's compare apples to apples and oranges to oranges: convert each given proper fraction into its decimal counterpart:

3 63/80 => 3 .788 approx.

3 1/5 => 3.2

3 11/20 => 3.55

It's now an easy matter to arrange these numbers from least to greatest:

3.2, 3.55, 3.79, or

3 1/5, 3 11/20, 3 63/80

7 0

3 years ago

How much is 5ml? How many teaspoons equals 5mls?

Makovka662 [10]

5ml is 0.00132086 and 1.01442 teaspoons equals to 5mls

6 0

3 years ago

Five plus three equals

8_murik_8 [283]

Answer: 8

Step-by-step explanation:

5 chicken nuggets + 3 more chicken nuggets equals 8

5 0

3 years ago

Read 2 more answers

Es 18 de junio de 1815, las tropas napoleónicas se encuentran justo adelante, tu eres el ingeniero en balística y el general Wel

Airida [17]

Answer:

89.1° or -1.4°

Step-by-step explanation:

1. Location:

You are on the Mont-Saint-Jean escarpment, near the Belgian town of Waterloo.

The French troops are about 50 m below you and 1.2 km distant.

2. Finding the firing angle

Data:

R = 1200 m

u = 600 m/s

h = -50 m (the height of the target)

a = 9.8 m/s²

We have two conditions.

Horizontal distance

(1) 1200 = 600t cosθ

Vertical distance

(2) -50 = 600t sinθ - 4.9t²

Divide each side of (1) by 600cosθ.

$(3) \, t =\dfrac{2}{\cos \theta}$

Substitute (3) into (2)

$-50 = 600t \sin \theta - 4.9t^{2} = 600 \left( \dfrac{2}{\cos \theta} \right ) \sin \theta - 4.9 \left( \dfrac{2}{\cos \theta} \right )^{2}\\\\(4) \, -50 = 1200 \tan \theta - \dfrac{19.6}{\cos^{2} \theta}$

Recall that

(5) sec²θ = 1/cos²θ = tan²θ + 1

Substitute (5) into (4)

$-50 = 1200 \tan \theta - 19.6 \left(\tan^{2} \theta}+ 1\right )$

Set up a quadratic equation

$\begin{array}{rcl}-50 & = & 1200 \tan \theta - 19.6\tan^{2} \theta -19.6 \\0 & = & 1200 \tan \theta - 19.6\tan^{2} \theta + 30.4\\0 & =&19.6\tan^{2} \theta - 1200 \tan \theta - 30.4\\0 & =&\tan^{2} \theta - 61.224 \tan \theta - 1.551\\\end{array}$

Solve for θ

Use the quadratic formula.

tanθ = 61.249 or -0.025

θ = arctan(61.249) = 89.1° or

θ = arctan(-0.025) = -1.4°

3 0

3 years ago

PLZ HELP ME NOW.....

Likurg_2 [28]

A- solve bracket first so

3/4 + 2/9 +5/12 then multiply by 3.6 = 5

do the same with the rest and u get

A=5

B=1

C=15

D=3

please mark brainliest

5 0

3 years ago