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Ilya [14]
2 years ago
10

1 of 5

Mathematics
1 answer:
miss Akunina [59]2 years ago
8 0

Answer:

£15

Step-by-step explanation:

Angad : Nick = 5 : 1

Let

Nick share = x

Angad share = x + £60

Angad : Nick

5 : 1 = x + £60 : x

5/1 = x + 60 / x

Cross product

5 * x = 1 * x + 60

5x = x + 60

5x - x = 60

4x = 60

x = 60/4

x = 15

Nick get £15

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Answer my question for brainiest
11Alexandr11 [23.1K]

Answer:

-13 = n - 4

Step-by-step explanation:

-13 is four less than a number n

so four less than n  can be written as n - 4

-13 = n - 4

n= -9

8 0
3 years ago
Find the dimensions of the rectangle with largest area that can be inscribed in an equilateral triangle with sides of 1 unit, if
prohojiy [21]
<span>Maximum area = sqrt(3)/8 Let's first express the width of the triangle as a function of it's height. If you draw an equilateral triangle, then a rectangle using one of the triangles edges as the base, you'll see that there's 4 regions created. They are the rectangle, a smaller equilateral triangle above the rectangle, and 2 right triangles with one leg being the height of the rectangle and the other 2 angles being 30 and 60 degrees. Let's call the short leg of that triangle b. And that makes the width of the rectangle equal to 1 minus twice b. So we have w = 1 - 2b b = h/sqrt(3) So w = 1 - 2*h/sqrt(3) The area of the rectangle is A = hw A = h(1 - 2*h/sqrt(3)) A = h*1 - h*2*h/sqrt(3) A = h - 2h^2/sqrt(3) We now have a quadratic equation where A = -2/sqrt(3), b = 1, and c=0. We can solve the problem by using a bit of calculus and calculating the first derivative, then solving for 0. But since this is a simple quadratic, we could also take advantage that a parabola is symmetrical and that the maximum value will be the midpoint between it's roots. So let's use the quadratic formula and solve it that way. The 2 roots are 0, and 1.5/sqrt(3). The midpoint is (0 + 1.5/sqrt(3))/2 = 1.5/sqrt(3) / 2 = 0.75/sqrt(3) So the desired height is 0.75/sqrt(3). Now let's calculate the width: w = 1 - 2*h/sqrt(3) w = 1 - 2* 0.75/sqrt(3) /sqrt(3) w = 1 - 2* 0.75/3 w = 1 - 1.5/3 w = 1 - 0.5 w = 0.5 The area is A = hw A = 0.75/sqrt(3) * 0.5 A = 0.375/sqrt(3) Now as I said earlier, we could use the first derivative. Let's do that as well and see what happens. A = h - 2h^2/sqrt(3) A' = 1h^0 - 4h/sqrt(3) A' = 1 - 4h/sqrt(3) Now solve for 0. A' = 1 - 4h/sqrt(3) 0 = 1 - 4h/sqrt(3) 4h/sqrt(3) = 1 4h = sqrt(3) h = sqrt(3)/4 w = 1 - 2*(sqrt(3)/4)/sqrt(3) w = 1 - 2/4 w = 1 -1/2 w = 1/2 A = wh A = 1/2 * sqrt(3)/4 A = sqrt(3)/8 And the other method got us 0.375/sqrt(3). Are they the same? Let's see. 0.375/sqrt(3) Multiply top and bottom by sqrt(3) 0.375*sqrt(3)/3 Multiply top and bottom by 8 3*sqrt(3)/24 Divide top and bottom by 3 sqrt(3)/8 Yep, they're the same. And since sqrt(3)/8 looks so much nicer than 0.375/sqrt(3), let's use that as the answer.</span>
7 0
3 years ago
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Notice the picture below

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5 0
3 years ago
Write an equation for the graph of each line.<br><br>​
emmasim [6.3K]

Answer:

5. y = 2x + 4

6. y = (-1/2)x - 2

Step-by-step explanation:

5. We want to find the slope-intercept form of this, which is y = mx + b, where m is the slope and b is the y-intercept.

Slope is change in y divided by change in x. Here, let's take two random points: (-2, 0) and (0, 4). Then we have:

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The y-intercept is where the line crosses the y-axis. We see it does so at the point (0, 4), so b = 4.

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6. Again, let's find the slope. Pick any two points: (-4, 0) and (0, -2). The slope will be:

m = (-2 - 0) / (0 - (-4)) = -2 / 4 = -1/2

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3 0
3 years ago
Read 2 more answers
I need help with this?
Dmitrij [34]

el triangulo que forma el radio es un triangulo equilátero y por lo tanto el lado del hexágono sera  de la misma medida que el radio:

lado = radio = 2 cm

como hay 6 lados, lo multiplicamos por 6 :

2x6 = 12 cm

entonces el perímetro del hexágono es 12 cm

Saludos¡

6 0
3 years ago
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