The answer in standard form is (x+5/2)^2+(y-2)^2=1
Answer:
EG = 16 and FH =22
Step-by-step explanation:
We know that the diagonals of a parallelogram bisect each other
so 2a = 3b+2
and 2a+3 = 6b-1
We know have a system of equations to solve
2a = 3b+2
2a+3 = 6b-1
Subtract 3 from each side
2a+3-3 = 6b-1-3
2a = 6b -4
Now we can set the 2 equations equal ( 2a = 3b+2 and 2a = 6b -4)
3b+2 = 6b-4
Subtract 3b from each side
3b-3b+2 = 6b-3b-4
2 = 3b-4
Add 4 to each side
2+4 = 3b-4+4
6 = 3b
Divide by 3
6/3 = 3b/3
2 =b
We want to find a
2a = 3b+2
Substitute in b=2
2a = 3(2) + 2
2a = 6+2
2a =8
Divide by 2
2a/2 =8/2
a = 4
Now that we know a and b
EG = 2a + 3b+2
= 2(4) + 3(2)+2
= 8+6+2
= 16
FH = 2a+3 + 6b-1
= 2(4) +3 +6(2)-1
= 8+3+12-1
= 23-1
= 22
The answer is 104.
1/4 of 104 is 26, 104 - 26 = 78
78 - 7 = $71
If the number you are rounding is followed by 5, 6, 7, 8, or 9, round the number up (+1).
If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down (no change).
I think you meant to write
(2 × 10⁶) × 0.00009
First, convert 0.00009 to scientific notation:
0.00009 = 9 × 10 ⁻⁵
Then
(2 × 10⁶) × 0.00009 = (2 × 10⁶) × (9 × 10 ⁻⁵)
… = (2 × 9) × (10⁶ × 10 ⁻⁵)
… = 18 × 10¹
… = 1.8 × 10²
