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Aleksandr-060686 [28]
3 years ago
10

ILL MARK BRAINLIEST

Biology
2 answers:
jok3333 [9.3K]3 years ago
8 0

Answer:

the answer is D

Explanation:

:) sorry im a bit late

oksano4ka [1.4K]3 years ago
3 0
It has a thick atmosphere of hydrogen and helium
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A population of wild-flowers was scored for flower color. There were 302 blue (BB) plants, 1857 violet (BR) plants and 811 red (
Paul [167]

Answer:

frequency of the blue (B) allele = 0.4142

frequency of the red (R) allele = 0.5858

The number of blue plants expected is 509.652

The number of red plants expected is 1019.304

The anticipated number of violet plants is 1441.341

Calculated chi square value

= 84.5320 + 42.5688 + 119.8692\\= 246.97

Explanation:

Frequency of blue allele is

Frequency of blue allele is equal to sum of frequency of BB and half of frequency of BR

\frac{302}{2970} + \frac{1}{2} \frac{1857}{2970} \\= 0.1016 + 0.3126\\= 0.4142

Frequency of other allele

1- 0.4142\\= 0.5858

Chi Square test

See the attached file

The number of blue plants expected is 509.652

The number of red plants expected is 1019.304

The anticipated number of violet plants is 1441.341

Calculated chi square value

= 84.5320 + 42.5688 + 119.8692\\= 246.97

7 0
3 years ago
Predict how many genetically different offspring could be produced by outcrossing two 2n=4 individuals (just account for indepen
Llana [10]

Answer:

16 genetically different offspring

Explanation:

This is the case as each parent has the ability to produce 4 uniquely different gametes through independent assortment. With such a scenario where each parent can product 4 uniquely different gametes multiplied by 4 parents, you have 16 offspring. So there's the possibility of producing 16 offspring that are unique.

4 0
3 years ago
Two independently segregating genes determine kernel color in wheat. Red color results from at least one dominant allele in both
Lera25 [3.4K]

Answer:

a) The expected phenotype of the F1 plants is 100% RrBb, red kernels.

b) The expected phenotypic classes in the F2 are: 9:3:3:1

   9/16 R-B-, 3/16 rrB-, 3/16 R-bb,  1/16 rrbb

   Proportions 9:6:1.

9/16 Red kernel (R-B-), 6/16 Brown kernel (rrB- + R-bb), 1/16 White kernel (rrbb)    

Explanation:

<u>Available data:</u>

  • red kernel: R-B-
  • brown kernel: R-bb or rrB-
  • white kernel: rrbb

1º Cross)  RRBB      x      rrbb

F1)             100% RrBb (red kernels)

2ºCross)   RrBb       x       RrBb

Gametes)  RB                   RB

                  Rb                   Rb

                  rB                    rB

                  rb                    rb

Punnet Square)      RB           Rb         rB         rb

                 RB      RRBB      RRBb     RrBB     RrBb

                 Rb      RRBb      RRbb     RrBB     Rrbb

                 rB       RrBB       RrBb      rrBB      rrBb

                 rb       RrBb       Rrbb       rrBb     rrbb

F2)  Phenotypic classes:

       <em>9/16 R-B-</em>

<em>        3/16 rrB-</em>

<em>        3/16 R-bb</em>

<em>        1/16 rrbb</em>

      Phenotypic proportions:

      <em>9/16 Red kernel (R-B-)</em>

<em>       6/16 Brown kernel (rrB- + R-bb)</em>

<em>       1/16 White kernel (rrbb)         </em>                      

7 0
3 years ago
5. If an organism has 5 pairs of chromosomes and no crossing over occurs, how many different
Tom [10]

Answer:

In spite of the fact that he didn't have any acquaintance with it, Walther Flemming really noticed spermatozoa going through meiosis in 1882, yet he confused this cycle with mitosis. Regardless, Flemming saw that, dissimilar to during standard cell division, chromosomes happened two by two during spermatozoan improvement. This perception, continued in 1902 by Sutton's careful estimation of chromosomes in grasshopper sperm cell improvement, given conclusive insights that cell division in gametes was not simply customary mitosis. Sutton showed that the quantity of chromosomes was decreased in spermatozoan cell division, a cycle alluded to as reductive division. Because of this cycle, every gamete that Sutton noticed had one-a large portion of the hereditary data of the first cell.

Explanation:

3 0
3 years ago
The cell is going through which subphase of interphase
sukhopar [10]
Is there a picture that goes along with this question?
8 0
3 years ago
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