Ammonia gas will have a mass of 3.17grams.
HOW TO CALCULATE MASS:
- The mass of a substance can be calculated by multiplying the number of moles in the substance by its molar mass.
- However, to calculate the number of moles present in the ammonia gas given in this question, we use the formula as follows:
where;
- P = pressure (atm)
- V = volume (L)
- n = number of moles (mol)
- R = gas law constant
- T = temperature
n = PV ÷ RT
n = (1.2 × 3.7) ÷ (0.0821 × 290)
n = 4.44 ÷ 23.81
n = 0.186mol
- Mass of ammonia gas = 3.17g
- Therefore, the mass of ammonia gas is 3.17grams.
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Answer:
d. there is a net consumption of water and carbon dioxide
Explanation:
Photosynthesis, is the process whereby light energy is transform into chemical energy by
green plants and other photosynthesis capable organisms . In the process of photosynthesis, light energy is captured by green plants which it uses to convert carbon dioxide water, and minerals into energy-rich organic compounds and oxygen is evolved as a byproduct.
It is a chemical reaction taking place inside a plant, resulting in the production of food for the survival of the plant.
Photosynthesis takes place in the leaves of a plant in the presence of sunlight and.
Plants<span> have two </span>transport<span> systems to move food, </span>water and minerals<span> through their roots, stems and leaves. These systems use continuous tubes called xylem and phloem, and together they are known as </span>vascular<span> bundles. Thank you for your time and I hope this has helped you. See you next time brainy:)</span>
In 250 mL of volumetric flask add 0.975875 grams of
and dissolve it in the 250 mL of water.
Given:
The solid of calcium fluoride.
To prepare:
The 250 mL solution of 0.100 M of fluoride ions from solid calcium fluoride.
Method:
Molarity of the fluoride ion solution needed = M = 0.100 M
The volume of the fluoride ion solution needed = V = 250 mL
![1 mL = 0.001L\\V=250 mL=250\times 0.001 L=0.250 L](https://tex.z-dn.net/?f=1%20mL%20%3D%200.001L%5C%5CV%3D250%20mL%3D250%5Ctimes%200.001%20L%3D0.250%20L)
The moles of fluoride ion needed = n
According to the definition of molarity:
![M=\frac{n}{V}\\0.100M=\frac{n}{0.250 L}\\n=0.100M\times 0.250 L=0.025 mol](https://tex.z-dn.net/?f=M%3D%5Cfrac%7Bn%7D%7BV%7D%5C%5C0.100M%3D%5Cfrac%7Bn%7D%7B0.250%20L%7D%5C%5Cn%3D0.100M%5Ctimes%200.250%20L%3D0.025%20mol)
Moles of fluoride ion = 0.025 mol
We know that solid calcium fluoride dissolves in water to give calcium ions and fluoride ions.
![CaF_2(s)\rightarrow Ca^{2+}(aq)+2F^-(aq)](https://tex.z-dn.net/?f=CaF_2%28s%29%5Crightarrow%20Ca%5E%7B2%2B%7D%28aq%29%2B2F%5E-%28aq%29)
According to reaction, 2 moles of fluoride ions are obtained from 1 mole of calcium fluoride, then 0.025 moles of fluoride ions will be obtained from:
![=\frac{1}{2}\times 0.025 mol=0.0125 \text{mol of } CaF_2](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%200.025%20mol%3D0.0125%20%5Ctext%7Bmol%20of%20%7D%20CaF_2)
Moles of calcium fluoride = 0.0125 mol
Mass of calcium fluoride needed to prepare the solution :
![=0.0125 mol\times 78.07 g/mol=0.975875 g](https://tex.z-dn.net/?f=%3D0.0125%20mol%5Ctimes%2078.07%20g%2Fmol%3D0.975875%20g)
Preparation:
- Weight 0.975875 grams of calcium fluoride
- Add weighed calcium fluoride to a volumetric flask of the labeled volume of 250 mL.
- Now add a small amount of water to dissolve the calcium fluoride completely.
- After this add more water up to the mark of the volumetric flask of volume 250 mL.
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Answer:
p=27.8atm
Explanation:
P = 27.8atm
At what temperature will 5.00 g of Cl2 exert a pressure of 900. mmHg at a volume of 750.