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myrzilka [38]
3 years ago
15

During photosynthesis, ________.

Chemistry
1 answer:
ludmilkaskok [199]3 years ago
5 0

Answer:

d. there is a net consumption of water and carbon dioxide

Explanation:

Photosynthesis, is the process whereby light energy is transform into chemical energy by

green plants and other photosynthesis capable organisms . In the process of photosynthesis, light energy is captured by green plants which it uses to convert carbon dioxide water, and minerals into energy-rich organic compounds and oxygen is evolved as a byproduct.

It is a chemical reaction taking place inside a plant, resulting in the production of food for the survival of the plant.

Photosynthesis takes place in the leaves of a plant in the presence of sunlight and.

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What 3 things will you do to dissolve a solid (salt) faster in a liquid (water)
Dmitriy789 [7]

Answer:

There are three ways to make solids dissolve faster: Break the solute into smaller pieces. Stir the mixture. * Heat the mixture.

Explanation:

Substances can dissolve in water three ways—by dissociation, dispersion, and ionization.

6 0
2 years ago
Acetic acid (CH3COOH) is a weak acid that partially dissociates in water. Given the reaction CH3COOH(aq) ↔ CH3COO−(aq) + H+(aq)
likoan [24]

Answer:

The correct answer is: 1.035 x 10⁻³ M

Explanation:

The dissociation equilibrium for acetic acid (CH₃COOH) is the following:

CH₃COOH(aq) ↔ CH₃COO⁻(aq) + H⁺(aq)  Kc = 1.8 x 10⁻⁵

The expression for the equilibrium constant (Kc) is the ratio of concentrations of products over reactants. The products are acetate ion (CH₃COO⁻) and hydrogen ion (H⁺) while the reactant is acetic acid (CH₃COOH):

Kc=\frac{[CH_{3} COO^{-} ][H^{+} ]}{[CH_{3} COOH]}= 1.8 x 10^{-5}

Given: [CH₃COOH]= 0.016 M and [CH₃COO⁻]= 0.92 M, we replace the concentrations in the equilibrium expression and we calculate [H⁺]:

\frac{(0.016 M)[H^{+} ]}{(0.92M)}= 1.8 x 10^{-5}

⇒[H⁺]= (1.8 x 10⁻⁵)(0.92 M)/(0.016 M)= 1.035 x 10⁻³ M

8 0
3 years ago
In the naturally occurring D series of ketoses, the carbonyl group is found on carbon number ___________, whereas in aldoses, th
Elena-2011 [213]

Answer:

second carbon atom from the  end

end carbon atom

Explanation:

Carbohydrates are naturally occurring organic compounds containing carbon, hydrogen and oxygen. The general molecular formula of Carbohydrates is C_x(H_2O)_y.

Carbohydrates can be classified based on structures,

Carbohydrates with the structure of alkanals (-CHO) are known as aldose while those of the structure of alkanones (C=O) are known as ketose.

In stereochemistry , D series is a kind of configurational arrangement where the hydroxyl group attaches itself to the right hand side.

Thus; in naturally occurring D series of ketoses, the carbonyl group is found on carbon number <u>second carbon atom from the  end </u>whereas in aldoses, the carbonyl group is found on carbon number <u> end carbon atom.</u>

7 0
3 years ago
What is the mass number of chlorine?
Anastasy [175]

Answer:

Explanation:

35.453 u

7 0
2 years ago
I need to make up an experiment !! Please help
katen-ka-za [31]

Question: Baking a Cake Without Flour.

Hypothesis: I think that when I remove the flour from the standard cake recipe, I'll end up with a flat but tasty cake.

Procedure: I baked two cakes during my experiment. For my control, I baked a cake following a normal recipe. I used the Double Fudge Cake recipe on page 292 of the Betty Crocker Cookbook. For my experimental cake, I followed the same recipe but left out the flour. I first obtained a 2-quart mixing bowl.  

Results: My control cake, which I cooked for 25 minutes, measured 4 cm high.  Eight out of ten tasters that I picked at random from the class found it to be an acceptable dessert. After 25 minutes of baking, my experimental cake was 1.5 cm high and all ten tasters refused to eat it because it was burnt to a crisp.

What did I learn?/Conclusion: Since the experimental cake burned, my results did not support my hypothesis.  I think that the cake burned because it had less mass, but cooked for the same amount of time.  I propose that the baking time be shortened in subsequent trials.

-

I hope this helped :))

7 0
2 years ago
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