Answer:
B
Explanation:
Particles in a solid have fixed locations in a volume that does not change. Solids have a definite volume and shape because particles in a solid vibrate around fixed locations.
Answer:
OH−(aq), and H+(aq)
Explanation:
Redox reactions may occur in acidic or basic environments. Usually, if a reaction occurs in an acidic environment, hydrogen ions are shown as being part of the reaction system. For instance, in the reduction of the permanganate ion;
MnO4^-(aq) + 8H^+(aq) +5e-------> Mn^2+(aq) + 4H2O(l)
The appearance of hydrogen ion in the reaction equation implies that the process takes place under acidic reaction conditions.
For reactions that take place under basic conditions, the hydroxide ion is part of the reaction equation.
Hence hydrogen ion and hydroxide ion are included in redox reaction half equations depending on the conditions of the reaction whether acidic or basic.
Answer: Meniscus
Explanation: There is a condition on reading volumes. For concave meniscus read volume in the lower part and for convex meniscus read volume at the upper part.
<span>Saturated sodium chloride
is used to transfer the product rather than water since it is not polar and
rinsing the product with water would revert any 4-methylcyclohexene back to
4-methylcyclohexanol in the Hickman Head and thus lowering the percent yield;
using water would shift the equilibrium towards the reactants. Also
sodium chloride removes the small amount of phosphoric acid and also a small
amount of water. If one were to add water, both 4-methylcyclohexene and
phosphoric acid are partially soluble making difficult to remove the water
later; sodium chloride makes the water less reactive so easier to remove by
making the aqueous later more polar.</span>
Answer:
0.13 M
Explanation:
The reaction equation is;
NaOH(aq) + KHC8H4O4(aq) ------> KNaC8H4O4(aq) + H2O(l)
Molar mass of KHP = 204.22 g/mol
Amount of KHP= mass/ molar mass = 0.3365 g/204.22 g/mol = 1.65 × 10^-3 moles
n= CV
Where;
C= concentration
V= volume in dm^3
n= number of moles
C= n/V = 1.65 × 10^-3 moles × 1000/250 = 6.6 × 10^-3 M
If 1 mole of KHP reacts with 1 mole of NaOH
1.65 × 10^-3 moles of KHP will react with 1.65 × 10^-3 moles of NaOH
From
n= CV
We have that only 12.44 ml of NaOH reacted
C= n/V = 1.65 × 10^-3 moles × 1000/12.44
C= 0.13 M
At the equivalence point, the KHP solution turned light pink.
