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Shkiper50 [21]
3 years ago
9

If you wanted to make a crucible for melting sodium (Na), which metal would be most suitable for that purpose

Chemistry
1 answer:
Andreyy893 years ago
7 0
Calcium would be best suitable
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What are the advantages and disadvantages of fission?
viktelen [127]

<u>Advantages of Nuclear Fission</u>

  • Nuclear fission provides cheapest energy . Almost 10% of electricity used in the world is obtained from the fission reaction
  • It offers a low-emission energy solution since there is no carbon dioxide gas emitted during the  nuclear fission reaction
  • A well controlled and maintained nuclear reactor can produce energy for 36 to 40 months so works for .
  • It is a reliable source of energy as energy is obtained from uranium which is available is plenty.
  • It provides very concentrations of energy as it can provide large amount of energy from small amount of fuel.
  • The reaction gives less annual mortality rate of any energy resource with 90 deaths per trillion kilowatt hours

<u>Disadvantages of Nuclear Fission </u>

  • It is dangerous and  also explosive.
  • It creates harmful and radioactive waste products.
  • It is not a renewable energy resource like solar and wind energy
  • It can develop long-term health issues for people exposed to then radioactive waves.
  • It involves high cost in installation of the reactors.
5 0
3 years ago
In order to prepare 50.0 mL of 0.100 M NaOH you will add _____ mL of 1.00 M NaOH to _____ mL of water
FinnZ [79.3K]

The question requires us to complete the sentence regarding the preparation of a more dilute NaOH solution (0.100 M, 50.0 mL) from a more concentrated NaOH solution (1.00 M).

Analyzing the blank spaces that we need to fill in the sentence, we can see that we must provide the volume of the more concentrated solution and the volume of water necessary to prepare the solution.

We can use the following equation to calculate the volume of more concentrated solution required:

\begin{gathered} C_1\times V_1=C_2\times V_2 \\ V_1=\frac{C_2\times V_2}{C_1} \end{gathered}

where C1 is the concentration of the initial solution (C1 = 1.00 M), V1 is the volume required of the inital solution (that we'll calculate), C2 is the concentration of the final solution (C2 = 0.100 M) and V2 is the volume of the final solution (V2 = 50.0 mL).

Applying the values given by the question to the equation above, we'll have:

\begin{gathered} V_1=\frac{C_2\times V_2}{C_1} \\ V_1=\frac{0.100M_{}\times50.0mL_{}}{1.00M_{}}=5.00mL \end{gathered}

Thus, we would need 5.00 mL of the more concentrated solution.

Since the volume of the final solution is 50.0 mL and it corresponds to the volume of initial solution + volume of water, we can calculate the volume of water necessary as:

\begin{gathered} \text{final volume = volume of initial solution + volume of water} \\ 50.0mL=5.00mL\text{ + volume of water} \\ \text{volume of water = 45.0 mL} \end{gathered}

Thus, we would need 45.0 mL of water to prepare the solution.

Therefore, we can complete the sentence given as:

<em>"In order to prepare 50.0 mL of 0.100 M NaOH you will add </em>5.00 mL<em> of 1.00 M NaOH to </em>45.0 mL<em> of water"</em>

5 0
1 year ago
A block of aluminum occupies a volume of 15.0 mL and weighs 40.5 g. What is its density? Answer in g/mL.
solong [7]

Answer:

The answer is

<h2>2.7 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

Density =  \frac{mass}{volume}

From the question

mass of aluminum = 40.5 g

volume = 15 mL

Substitute the values into the above formula and solve for the density

We have

Density =  \frac{40.5}{15}

We have the final answer as

<h3>2.7 g/mL</h3>

Hope this helps you

8 0
4 years ago
How does sand becomes a form
Sonbull [250]
I think sand is just glass and other stuff
6 0
3 years ago
Read 2 more answers
Do the following problem using significant figures.<br> 4.5 cm x 2000.0 cm x 4 cm =<br> I<br> cm^3
Anon25 [30]

Given :

Measurements 4.5\ cm\times 2000.0\ cm\times 4\ cm .

To Find :

The multiplication using significant figures .

Solution :

We know , the least number of significant figures in any number of the problem determines the number  of significant figures in the answer.

So , significant figure( S.F) in 4.5 cm is 2 .

S.F in 2000.0 cm is 5 .

S.F in 4 cm is 1 .

So , minimum S.F is 1 .

Therefore , S.F of their product is 1 .

Now , multiplying them we will get :

M=4.5\times 2000.0\times 4 \ cm^3\\\\M=36000\ cm^3

Now , converting 36000 in 1 significant digit .

First we will write it in exponential 2 S.F form.

3.6\times 10^4 \ cm^3

Now , to convert 3.6 into 1 S.F we should round off this .

So , round off 3.6 we will get 4 .

Therefore , The multiplication using significant figures is 4\times 10^4\ cm^3 .

Hence , this is the required solution .

3 0
3 years ago
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