Answer:
Step-by-step explanation:
hello :
the numbers a1 , a2 ,a3
form three consecutive members of an arithmetic sequence means : 2a2 = a1+,a3
2 In(x + 3) = In(x + 2)+In(4x + 8)....(*)
now solve this equation use this note :
ln a^n = alna and : lna+lnb =lnab lna =lnb means : a=b ...a , b positif numbers
(*) equivaut : In(x + 3)² = In(x + 2)(4x + 8) and : x + 2 ,x + 3 , 4x + 8
are positifs numbers
(x + 3)² = (x + 2)(4x + 8)
x²+6x+9 = 4x²+16x+16
3x²+10x+7 =0
delta =10²-4(3)(7) 100 -84 = 4²
x1 = (-10-4)/6 = -7/3 reused
x 2 = (-10+4)/6 = -1 reused
conclusion : a. Such x does not exist.
