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kiruha [24]
2 years ago
15

) As an ice cube melts its surface area is decreasing at a rate of 6cm2/sec. Find the rate at which the length of each side is d

ecreasing at the moment when each side has length 2 cm. [Hint: a cube has 6 sides and each side has area x 2 where x is the side length]
Mathematics
1 answer:
RideAnS [48]2 years ago
6 0

Answer:

<u>The rate of decreasing of the length is 0.25 cm/s.</u>

Step-by-step explanation:

The surface area of the ice cube is:

A_{ice}=6x^{2}

Where x is the side of the cube.

Let's take the derivative of A with respect to "t" to get the rate of change.

\frac{dA_{ice}}{dt}=12x\frac{dx}{dt}

We know that dA/dt = 6 cm²/s and x is 2 cm, so we just need to solve it for dx/dt which is the rate change of the length.

6=12(2)\frac{dx}{dt}

\frac{dx}{dt}=\frac{1}{4}\: cm/s

Therefore, <u>the rate of decreasing of the length is 0.25 cm/s.</u>

I hope it helps you!

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What is the slope of the line?
lutik1710 [3]

Answer:

todavía no me la sé pero al rato te mando la respuesta

7 0
3 years ago
A new movie opened in a local theater. On opening day, 985 people saw the movie. Each day after opening day, the number of peopl
zysi [14]

Answer:

About 3891 people saw that movie.

Step-by-step explanation:

Day 1: 985 people

Day 2: (985*8)/10 (20% gone) = 788

Day 3: (788*8)/10 (20% gone) = 630.4

Day 4: (630.4*8)/10 (20% gone) = 504.32

Day 5: (504.32*8)/10 (20% gone) = 403.456

Day 6: (403.456*8)/10 (20% gone) = 322.7648

Day 7: (322.7648*8)/10 (20% gone) = 258.21184

Adding this up:

985+788+630.4+504.32+403.456+322.7648+258.21184=

985+788+630+504+403+323+258=3891

4 0
3 years ago
Let X be the temperature in at which a certain chemical reaction takes place, and let Y be the temperature in (so Y = 1.8X + 32)
Black_prince [1.1K]

Answer:

See explanation

Step-by-step explanation:

Solution:-

The random variable, Y be the temperature of chemical reaction in degree fahrenheit be a linear expression of a random variable X : The  temperature in at which a certain chemical reaction takes place.

                             Y = 1.8*X + 32

- The median of the random variate "X" is given to be equal to "η". We can mathematically express it as:

                             P ( X ≤ η ) = 0.5

- Then the median of "Y" distribution can be expressed with the help of the relation given:

                             P ( Y ≤ 1.8*η + 32 )

- The left hand side of the inequality can be replaced by the linear relation:

                             P ( 1.8*X + 32 ≤ 1.8*η + 32 )

                             P ( 1.8*X ≤ 1.8*η )   ..... Cancel "1.8" on both sides.

                            P ( X ≤ η ) = 0.5 ...... Proven

Hence,

- Through conjecture we proved that: (1.8*η + 32) has to be the median of distribution "Y".

b)

- Recall that the definition of proportion (p) of distribution that lie within the 90th percentile. It can be mathematically expressed as the probability of random variate "X" at 90th percentile :

                             P ( X ≤ p_.9 ) = 0.9 ..... 90th percentile

- Now use the conjecture given as a linear expression random variate "Y",

          P ( Y ≤ 1.8*p_0.9 + 32 ) = P ( 1.8*X + 32 ≤ 1.8*p_0.9 + 32 )

                                                 = P ( 1.8*X ≤ 1.8*p_0.9 )

                                                 = P ( X  ≤ p_0.9 )

                                                 = 0.9

- So from conjecture we saw that the 90th percentile of "X" distribution is also the 90th percentile of "Y" distribution.

c)

- The more general relation between two random variate "Y" and "X" is given:

                            Y = aX + b

Where, a : is either a positive or negative constant.

- Denote, (np) as the 100th percentile of the X distribution, so the corresponding 100th percentile of the Y distribution would be : (a*np + b).

- When a is positive,

                   P ( Y ≤ a*p_% + b ) = P ( a*X + b ≤ a*p_% + b )

                                                 = P ( a*X ≤ a*p_% )

                                                 = P ( X  ≤ p_% )

                                                 = np_%        

- When a is negative,

                   P ( Y ≤ a*p_% + b ) = P ( a*X + b ≤ a*p_% + b )

                                                 = P ( a*X ≤ a*p_% )

                                                 = P ( X  ≥ p_% )

                                                 = 1 - np_%        

                                                           

4 0
2 years ago
Determine whether the relation represents a function.
-Dominant- [34]

Answer:

it does not because it would not pass the straight line test

Step-by-step explanation:

sorry if its wrong and btw your cute

6 0
2 years ago
A group of 100 students took a quiz. Their average score was 76 points. If the average score for the boys was 80 points and the
sveta [45]

Answer:

The number of girls participated in quiz is 40 .

Step-by-step explanation:

Given as :

Total number of students took quiz = 100

Average score of 100 students = 76 points

The Average score of boys = 80 points

The Average score of girls = 70 points

Let The number of boys participated in quiz = b

Let The number of girls participate in quiz = g

Now, According to question'

Total number of students took quiz = number of boys participated in quiz + number of girls participated in quiz

Or, b + g = 100           ........A

<u>Again</u>

∵ Average score of 100 students = 76 points

∴ Total score of 100 students = 76 × 100 = 7600

So, Average score of boys × number of boys participated + Average score of girls × number of girls participated = Total score of 100 students

Or, b × 80 + g × 70 = 7600

Or, 80 b + 70 g = 7600             .........B

Now, Solving equation A and B

(80 b + 70 g ) - 70 ×( b + g ) = 7600 - 70 × 100

I.e (80 b - 70 b) + (70 g - 70 g) = 7600 - 7000

Or, 10 b + 0 = 600

∴  b = \dfrac{600}{10}

i.e b = 60

So, The number of boys participated in quiz = b = 60

Put the value of b into eq A

∵ b + g = 100

So, g = 100 - b

Or, g = 100 - 60

i.e g = 40

So, The number of girls participated in quiz = g = 40

Hence, The number of girls participated in quiz is 40 . Answer

6 0
3 years ago
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