The angle between reflected ray and the normal line is

How much distance does it take to stop a car going 30 m/s (67 mph) if the brakes can apply a force equal to one half the car’s w

denpristay [2]

Answer:

0

rqc3fgt9uwgtd.ojbxrfdgi8ubvg iohy

5 0

2 years ago

Match the block to its correct density. 1. Block A 0.64 Kg/L 2. Block B 0.917 kg/L 3. Block C 0.70 Kg/L 19.3 kg/L 4. Block D 3.5

Sedbober [7]

Answer:

quit school aghahahha

Explanation:

xD

4 0

3 years ago

The coil springs on a car's suspension have a value of k = 64000 N/m. When the

AlladinOne [14]

80 joule is momentarily stored in each spring

Solution:

Given that,

The coil springs on a car's suspension have a value of k = 64000 N/m

When the car strikes a bump the springs briefly compress by 5.0 cm (.05 m)

By compressing the spring, we apply a force over a distance

As a result we have done work on the spring

Doing work means that we have transferred energy to spring in form of elastic potential

Therefore,

k = 64000 N/m

x = 0.05m

The elastic potential energy is given as:

$PE = \frac{1}{2}kx^2$

Where, "k" is the spring constant and "x" is the displacement

$PE = \frac{1}{2} \times 64000 \times 0.05^2\\\\PE = 32000 \times 0.0025\\\\PE = 80$

Thus 80 joule is momentarily stored in each spring

8 0

3 years ago

You are on the roof of the physics building, 46.0 above the ground . Your physics professor, who is 1.80 tall, is walking alongs

nekit [7.7K]

There is one mistake in the question as unit of height of building is not given.So I assume it as meter.The complete question is here

You are on the roof of the physics building, 46.0 m above the ground. Your physics professor, who is 1.80 m tall, is walking alongside the building at a constant speed of 1.20 m/s. If you wish to drop an egg on your professor’s head, where should the professor be when you release the egg? Assume that the egg is in free fall.

Answer:

d=3.67 m

Explanation:

Height of building=46.0 m

First we need to find time taken by egg to reach 1.80 m above the surface

So to find time use below equation

$S=vt+\frac{1}{2} gt^{2}\\ (46.0-1.80)m=(om/s)t+\frac{1}{2}(9.8m/s^{2} )t^{2}\\t=\sqrt{\frac{(46.0-1.80)m}{4.9} }\\ t=3.06s$

As velocity 1.20m/s is given and we have find time.So we can easily find the distance

So

$distance=velocity*time\\d=v*t\\d=(1.20m/s)*(3.06s)\\d=3.67m$

3 0

3 years ago

3 kids are pushing on a cart 2 are pushing north at 50 N each. The 3rd is pushing South at -90 N. The net force is _N?

scoray [572]

Answer:

Explanation:

When two forces act in the same direction , they add up and when they act in opposite direction , they subtract .

2 forces each of 50 N act in same direction , so they will add up to give resultant force of 100 N . Now third force acts in opposite direction so 100 N and - 90 N will subtract to give total resultant force .

Resultant force = 100 - ( - 90 ) = 190 N

So net force or resultant force = 190 N .

6 0

3 years ago