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elena55 [62]
3 years ago
14

After 2.0 s has elapsed on kara's watch, what does kara say the distance is between you and the laser pulse?

Physics
1 answer:
kakasveta [241]3 years ago
5 0

Answer:

huh?

Explanation:

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Which of the following statements about the periodic table is true?
skelet666 [1.2K]

Answer:

elements are the same columns are similar in there property

Explanation:

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Im pregnaunt at the age 12 what shall i do now ??<br><br> i do live my belly bump&lt;3
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theoretically speaking I don't even wanna believe it's possible but if it does then then you should check for abortion

8 0
3 years ago
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A person of mass m will bungee-jump from a bridge over a river where the height from the bridge to the river is h. The bungee co
Likurg_2 [28]

Answer:k_{min}=\frac{18mg}{h}

Explanation:

Given

mass of person is m

Distance between bridge and river is h

chord has an un-stretched length of \frac{2h}{3}

Let spring constant be k

Person will just stop before hitting the river

Conserve energy i.e. Potential Energy of Person is converted in to elastic energy of chord

mgh=\frac{kx^2}{2}

x=h-\frac{2h}{3}=\frac{h}{3}

mgh=\frac{kh^2}{18}

k=\frac{18mg}{h}

Thus k_{min}=\frac{18mg}{h}

5 0
3 years ago
What occurs when an object travels in a curved path
babymother [125]
<span>When an object travels in a curved path, there must be a force acting toward the center of the circular trajectory. This force is called "centripetal force", and it cause an acceleration of the object, called "centripetal acceleration". The effect of this acceleration is that the velocity of the object changes in direction: however if the circular motion is uniform, the speed (=the magnitude of the velocity) does not change. In this case, the magnitude of the centripetal force is given by
</span>F=m \frac{v^2}{r}<span>
where m is the mass of the object, v its velocity, and r the radius of the circular path.</span>
7 0
3 years ago
A ball is dropped from a rooftop 60m high. <br> How long is the ball in the air?
alina1380 [7]

Answer: 3.49 s

Explanation:

We can solve this problem with the following equation of motion:

y=y_{o}+V_{o}t-\frac{1}{2}gt^{2} (1)

Where:

y=0 m is the final height of the ball

y_{o}=60 m is the initial height of the ball

V_{o}=0 m/s is the initial velocity (the ball was dropped)

g=9.8 m/s^{2} is the acceleratio due gravity

t is the time

Isolating t:

t=\sqrt{\frac{2 y_{o}}{g}} (2)

t=\sqrt{\frac{2 (60 m)}{9.8 m/s^{2}}} (3)

Finally we find the time the ball is in the air:

t=3.49 s (4)

7 0
3 years ago
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