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elena55 [62]
3 years ago
14

After 2.0 s has elapsed on kara's watch, what does kara say the distance is between you and the laser pulse?

Physics
1 answer:
kakasveta [241]3 years ago
5 0

Answer:

huh?

Explanation:

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mihalych1998 [28]

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This will really help you learn a lot.

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4 years ago
a fast charged particle passes perpendicularly through a thin glass sheet of index of refraction 1.5. The particle emits light i
NeX [460]

The minimum speed of the particle is the Speed of light in glass is c/μ=2×108m/s.

<h3>Why is the refractive index important?</h3>

The higher the refractive index the slower the light travels, which causes a correspondingly increased change in the direction of the light within the material. What this means for lenses is that a higher refractive index material can bend the light more and allow the profile of the lens to be lower.

Refractive index values are usually determined at standard temperature. A higher temperature means the liquid becomes less dense and less viscous, causing light to travel faster in the medium.

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7 0
1 year ago
archer shoots his arrow towards a target at a distance of 90 m, and hits ‘bullseye’ . Calculate the acceleration and time taken
Cerrena [4.2K]
Answer:

Acceleration = 45m/s^2
Time = 2 s

Explanation:

6 0
4 years ago
James decides to walk home from school today. He lives 3 miles from school and can walk home in 45 minutes. At what rate is Jame
Kaylis [27]
B 1 mile/15 minutes is the right one
3 0
3 years ago
A 91.5 kg football player running east at 3.73 m/s tackles a 63.5 kg player running east at 3.09 m/s. what is their velocity aft
PIT_PIT [208]

Their velocity afterward is  v=3.467 m/s

Explanation:

Given:

Mass of the first football player= 91.5 kg

Initial velocity of the football player 3.73 m/s

Mass of second football player=63.56 kg

Initial velocity of the second football player=3.09 m/s

To find:

Final velocity of both players=?

Solution:

According to the law of conservation of momentum,

Initial momentum =final momentum

mathematically represented as  

m_1u_1+m_2u_2=m_1v_1+m_2v_2...........................(1)

where

u_1=intial velocity of the football player

u_2 = inital velocity of second football player

v_1=finall velocity of the  first football player

v_2=final velocity of second football player

after tackling , both the football players moves with the same velocity,

so v_1=v_2=v

Hence equation (1) becomes

m_1u_1+m_2u_2=(m_1+m_2)v

v=\frac{m_1u_1+m_2u_2}{(m_1+m_2)}

now substituting the values,

v=\frac{(91.5\times+3.73)+(63.5\times3.09)}{(91.5+63.5)}v=\frac{(341.29+196.210)}{155}

v=\frac{537.5}{155}

v=3.467 m/s

7 0
4 years ago
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