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2 years ago

How do the nitrogen and other matter in your body come from other living things in the environment.

Physics

1 answer:

kifflom [539]2 years ago

3 0

Answer:

Through Photosynthesis and Respiration Process.

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An average sleeping person metabolizes at a rate of about 80 W by digesting food or burning fat. Typically, 20% of this energy g

Leto [7]

Answer:

-4.7 x 10^-3 J/K-s

Explanation:

The Power generated by metabolizing food = 80 W

The watt W is equivalent to the Joules per sec J/s

therefor power = 80 J/s

20% of this energy is not used for heating, amount available for heating is

==> H = 80% of 80 = 0.8 x 80 = 64 J/s

The inner body temperature = 37 °C = 273 + 37 = 310 K

The entropy of this inner body ΔS = ΔH/T

ΔS = 64/310 = 0.2065 J/K-s

The skin temperature is cooler than the inner body by 7 °C

Temperature of the skin = 37 - 7 = 30 °C = 273 + 30 = 303 K

The entropy of the skin = ΔS = ΔH/T

ΔS = 64/303 = 0.2112 J/K-s

change in entropy of the person's body = (entropy of hot region: inner body) - (entropy of cooler region: skin)

==> 0.2065 - 0.2112 = -4.7 x 10^-3 J/K-s

8 0

3 years ago

Your car burns gasoline as you drive up a large mountain. What energy transformation is the car performing?

Sonja [21]

Your car is performing a transformation of energy of:

Chemical energy to Mechanical energy

The chemical is the gasoline which is then converted to fire as the car runs thus creating the movement of the car which is mechanical energy.

7 0

2 years ago

Read 2 more answers

An unknown immiscible liquid seeps into the bottom of an open oil tank. Some measurements indicate that the depth of the unknown

ira [324]

Answer:

The specific gravity of the unkown liquid is 15.

Explanation:

Gauge pressure, at the bottom of the tank in this case, can be calculated from

$P_{bot}=\gamma_{oil}h_1 + \gamma_{unk}h_2,$

where $h_1$ and $h_2$ are the height of the column of oil and the unkown liquid, respectively. Writing for $\gamma_{unk}$ , we have

$\gamma_{unk} = \frac{P_{bot} - \gamma_{oil}h_1}{h_2} = \frac{65\frac{kN}{m^2} - 8.5\frac{kN}{m^3}\times 5m}{1.5m} = \mathbf{15 \frac{kN}{m^3}}.$

Relative to water, the unknow liquid specific weight is 15 times bigger, therefore this is its specific gravity as well.

3 0

2 years ago

With which of the following statements would Whorf and Sapir agree?

ASHA 777 [7]

Hi!

The answer is B. Language influences how people understand their world.

Hope this helps!

-Payshence xoxo

6 0

2 years ago

Read 2 more answers

005 10.0 points

velikii [3]

Answer:

16.6 N

Explanation:

m = 0.52 kg, v₀ = 0, v = 8.6 m/s, t = 0.27 s

a = (v - v₀)/t

F = ma = m(v - v₀)/t = 0.52 (8.6 - 0)/0.27 = 16.6 N

8 0

2 years ago