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Dovator [93]
2 years ago
13

What is the acceleration of a ball thrown vertically upward in the presence of Earth’s

Physics
1 answer:
adelina 88 [10]2 years ago
8 0

Answer:

-9.8 m/s/s

Explanation:

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When an aluminum bar is connected between a hot reservoir at 720 K and a cold reservoir at 358 K, 3.00 kJ of energy is transferr
disa [49]

Answer:

a.  -4.166 J/K

b. 8.37 J/K

c. 4.21 J/K

d. entropy always increases.

Explanation:

Given :

Temperature at hot reservoir , $T_h$ = 720 K

Temperature at cold reservoir , $T_c$ = 358 K

Transfer of heat, dQ = 3.00 kJ = 3000 J

(a). In the hot reservoir, the change of entropy is given by:

$dS_h= -\frac{dQ}{t_h}$              (the negative sign shows the loss of heat)

$dS_h= -\frac{3000}{720}$

      =  -4.166 J/K

(b)  In the cold reservoir, the change of entropy is given by:

$dS_c= \frac{dQ}{t_c}$              

$dS_c= \frac{3000}{358}$

      =  8.37 J/K

(c). The entropy change in the universe is given by:

$dS=dS_h+dS_c$

    = -4.16+8.37

   = 4.21 J/K

(d). According to the concept of entropy, the entropy of the universe is always increasing and never decreasing for an irreversible process. If the entropy of universe decreases, it violates the laws of thermodynamics. Hence, in part (c), the result have to be positive.

5 0
3 years ago
*NEED THIS ANSWERED ASAP*
Musya8 [376]

Answer:

When the velocity is set to a constant value, the displacement increases with time but the acceleration remains zero

Explanation:

plato

4 0
2 years ago
What is the maximum force that could be applied to anterior cruciate ligament (ACL) if it has a diameter of 4.8 mm and a tensile
vovangra [49]

Answer:

Maximum force, F = 1809.55 N

Explanation:

Given that,

Diameter of the anterior cruciate ligament, d = 4.8 mm

Radius, r = 2.4 mm

The tensile strength of the anterior cruciate ligament, P=100\times 10^6\ N/m^2=10^8\ Pa

We need to find the maximum force that could be applied to anterior cruciate ligament. We know that the unit of tensile strength is Pa. It must be a type of pressure. So,

F=P\times A\\\\F=10^8\times \pi (2.4\times 10^{-3})^2\\\\F=1809.55\ N

So, the maximum force that could be applied to anterior cruciate ligament is 1809.55 N

4 0
3 years ago
Negative charges repel positive charges.<br> a. true or<br> b. false
arlik [135]
False they attract.. Remember opposites attract!
6 0
3 years ago
Impulse: A batter applies an average force of 8000 N to a baseball for 1.1 ms. What is the magnitude of the impulse delivered to
fiasKO [112]

The magnitude of the impulse delivered to the baseball by the bat is 8.8 Ns.

<h3>Impulse experienced by objects</h3>

The impulse experienced by any object is equal to the change in the momentum of the object.

The magnitude of the impulse delivered to the baseball by the bat is calculated by applying the following equation.

J = Ft

where;

  • F is applied force = 8000 N
  • t is time, = 1.1 ms

J = (8000) x (1.1 x 10⁻³)

J = 8.8 Ns

Thus, the magnitude of the impulse delivered to the baseball by the bat is 8.8 Ns.

Learn more about impulse here: brainly.com/question/229647

5 0
3 years ago
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