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Sidana [21]
3 years ago
14

I need help on this and the first person who will answer this correctly gets BRANLIST​

Physics
1 answer:
Nikolay [14]3 years ago
3 0

Answer:

i think it's b but i don't know for sure

Explanation:

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If two asteroids moved closer together, what would be the result on the gravitational force each asteroid exerts on the other?
spayn [35]
Gravitational force depends on inverse square law. That is, gravitational force is inversely proportional to square of distance between asteroids.
As distance between them decreases, gravitational force increases. Hence A is correct.
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A 50.0-kg bungee jumper steps off a bridge with a light bungee cord tied to her and to the bridge. The unstretched length of the
lina2011 [118]

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The the analysis for the free fall part should be done under the constant acceleration.

Explanation:

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Therefore, the the analysis for the free fall part should be done under the constant acceleration.

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3 years ago
If you were to apply a force of 15N to a medicine ball with a mass of 10kg, what would its acceleration be
tresset_1 [31]

One of the equations for force is:  Force = mass × acceleration.

The force and mass are given and so:

F=15N

m=10kg

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F=ma\\\\15=10(a)\\

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6 0
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Elements on the periodic table are organized by atomic number and then by __________ additional ways.
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Answer:B.2
Explaination

3 0
3 years ago
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two pendulums of lengths 100cm and 110.25cm start oscillating in phase. after how many oscillations will they again be in same p
goldfiish [28.3K]

Angular frequency of pendulum is given by

\omega = \sqrt{\frac{g}{l}}

for both pendulum we have

\omega_1 = \sqrt{\frac{9.81}{1.00}}

\omega_1 = 3.13 rad/s

For other pendulum

\omega_2 = \sqrt{\frac{9.81}{1.1025}}

\omega_2 = 2.98 rad/s

now we have relate angular frequency given as

[tex\omega_1 - \omega_2 = 3.13 - 2.98 = 0.15 rad/s[/tex]

now time taken to become in phase again is given as

t = \frac{2\pi}{\omega_1 - \omega_2}

t = \frac{2\pi}{0.15} = 41.88 s

now number of oscillations complete in above time

N = \frac{t}{\frac{2\pi}{\omega_1}}

N = \frac{41.88}{\frac{2\pi}{3.13}}

N = 21 oscillation


3 0
3 years ago
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