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3 years ago

6

A woman drives a golf ball off the tee to a speed of 28 m/s. The mass of the ball is 45 g and tIf the angle of the flight was in

itially 20ofrom the horizontal, how far would the ball go before it landed? (51 m) he time of contact was 6.0 ms.

1 answer:

Novay_Z [31]3 years ago

8 0

Answer:

456

Explanation:

impulse = Force x (time of contact)

this isn't really much information but hope this helps !: )

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A fleeing student covered a distance of 210 meters in 35 seconds. what is the student's speed in meters/second? what is the stud

snow_lady [41]

Explanation:

Given that,

A student covered a distance of 210 meters in 35 seconds.

We need to find the student's speed in meters/second and also in meters/minute.

Speed, v = distance (d)/time (t)

So,

$v=\dfrac{210\ m}{35\ s}\\\\=6\ m/s$

We know that, 1 minute = 60 seconds

$6\dfrac{m}{s}=6\times \dfrac{m}{(\dfrac{1}{60})\ \text{minutes}}\\\\=360\ \text{meters/minutes}$

Hence, the student's speed is 6 m/s or 360 meters/minute.

6 0

3 years ago

Two charges 5 c and 15 c are seperated by 10 cm. what is the electric force between them?

icang [17]

Answer:

6.75×10^13N

Explanation:

The electric force between the charges can be determined using coulombs law which states that 'the force of attraction between two charges is directly proportional to the product of the charges and inversely proportional to the square of their distance between them.

Mathematically, F = kq1q2/r² where;

q1 and q2 are the charges

r is the distance between the charges

F is the force of attraction

k is the coulombs constant

Given q1 = 5C q2 = 15C r = 10cm = 0.1m k = 9×10^9Nm²/C²

Substituting the given values in the formula we have;

F =9×10^9×5×15/0.1²

F = 6.75×10^11/0.01

F = 6.75×10^13N

Therefore the electric force between them is 6.75×10^13N

8 0

3 years ago

The rotational kinetic energy term is often called the kinetic energy in the center of mass, while the translational kinetic ene

weqwewe [10]

Answer:

C

Explanation:

The total kinetic energy is the sum of the kinetic energy in the center of mass (Rotational Kinetic energy) plus the kinetic energy of the center of mass( Translational Kinetic Energy).

The formula

$K_{tot} = K_{t} +K_{r}$ is applicable only when

The moment of inertia must be taken about an axis through the center of mass.

6 0

4 years ago

Read 2 more answers

A spherical snowball is melting in such a way that its radius is decreasing at rate of 0.1 cm/min. At what rate is the volume of

andrew11 [14]

Answer:

$\frac{dV}{dt}=-78,4\pi \frac{cm^{3} }{min}$

Explanation:

Knowing that the volume of a sphere is V=(4/3)πr³ and $\frac{dr}{dt}=-0.1\frac{cm}{min}$

We must find $\frac{dV}{dt}=?$ when r=14cm

V=(4/3)πr³ ⇒

$\frac{dV}{dt}=\frac{4}{3}\pi3r^{2}\frac{dr}{dt}\\\frac{dV}{dt}=4\pi r^{2}(-0.1\frac{cm}{min})$

and r=14cm then

$\frac{dV}{dt}=4\pi(14cm)^{2}(-0.1\frac{cm}{min})\\\frac{dV}{dt}=4\pi196cm^{2}(-0.1\frac{cm}{min})\\\frac{dV}{dt}=-78,4\pi \frac{cm^{3} }{min}$

Note: as you can see the relationship of change of r with respect to t is negative because it is a decrease, and also its volume ratio

4 0

4 years ago

Calculate the momentum of a 147 kg tiger running south at 14.7m/s.

Ganezh [65]

P=mv

2087.4 kg meter/second

7 0

3 years ago