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Serhud [2]
2 years ago
12

PLEASE ANSWER THIS ASAP!!!

Physics
1 answer:
Burka [1]2 years ago
5 0

Answer:

I guess B

Explanation:

Because it stop by it self so that is digital

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the density of ice is 917.what fraction of the volume of a piece of ice will be above the liquid when floating in fresh water
yulyashka [42]

Answer:

8.3\,\% of that piece of ice would be above the freshwater.  Assumptions:

  • the density of the ice is \rho(\text{ice}) = 917\; \rm kg \cdot m^{-3}, and
  • the density of freshwater is \rho(\text{water}) = 1.00 \times 10^3\; \rm kg \cdot m^{-3} .

Explanation:

The volume of that chunk of ice can be split into two halves: volume above water V(\text{above}), and volume under water V(\text{under}). The mass of the whole chunk of ice would be:

m(\text{ice}) = \rho(\text{ice}) \cdot (V(\text{above}) + V(\text{under})).

Let g be the acceleration due to gravity. The gravity on the entire chunk of ice would be

\begin{aligned}&W(\text{ice}) \\ &= m({\text{ice}}) \cdot g \\ &= \rho(\text{ice}) \cdot (V(\text{above}) + V(\text{under})) \cdot g\end{aligned}.

On the other hand, the size of buoyant force on an object is equal to the weight of the liquid that it displaces. That is: F(\text{bouyancy}) = W(\text{water displaced}).

Recall that V(\text{above}) is the volume of the ice above the water, and V(\text{under}) is the volume of the ice under the water.

The mass of water displaced would be equal to:

\begin{aligned}& m(\text{water displaced}) \\ &= \rho(\text{water}) \cdot V(\text{water displaced}) \\ &= \rho(\text{water}) \cdot V(\text{under})\end{aligned}.

The weight of that much water would be

\begin{aligned} &W(\text{water displaced}) \\ &= m(\text{water displaced}) \cdot g \\ &= \rho(\text{water}) \cdot V(\text{under}) \cdot g \end{aligned}.

Apply the equation F(\text{bouyancy}) = W(\text{water displaced}). The bouyant force on this chunk of ice would be equal to \begin{aligned} &W(\text{water displaced}) = \rho(\text{water}) \cdot V(\text{under}) \cdot g \end{aligned}.

Since the ice is floating, the forces on it need to be balanced. In other words, \begin{aligned}W(\text{ice}) &= F(\text{bouyancy}) \\ &= \rho(\text{water}) \cdot V(\text{under}) \cdot g\end{aligned}.

On the other hand, recall that

\begin{aligned}&W(\text{ice}) = \rho(\text{ice}) \cdot (V(\text{above}) + V(\text{under})) \cdot g\end{aligned}.

Combine the two halves to obtain:

\begin{aligned}& \rho(\text{ice}) \cdot (V(\text{above}) + V(\text{under})) \cdot g \\ &= W(\text{ice}) = \rho(\text{water}) \cdot V(\text{under}) \cdot g\end{aligned}.

\begin{aligned}& \rho(\text{ice}) \cdot (V(\text{above}) + V(\text{under})) \cdot g = \rho(\text{water}) \cdot V(\text{under}) \cdot g\end{aligned}.

Divide both sides by g (assume that g \ne 0) to obtain:

\begin{aligned}& \rho(\text{ice}) \cdot (V(\text{above}) + V(\text{under})) = \rho(\text{water}) \cdot V(\text{under})\end{aligned}.

Rearrange to obtain:

\begin{aligned}& \frac{V(\text{under})}{V(\text{above}) + V(\text{under})} = \frac{\rho(\text{water})}{\rho(\text{ice})}\end{aligned}.

However, the question is asking for \displaystyle \frac{V(\text{above})}{V(\text{above}) + V(\text{under})}, the fraction of the volume above water. Note that

\begin{aligned}& \frac{V(\text{under})}{V(\text{above}) + V(\text{under})} + \frac{V(\text{above})}{V(\text{above}) + V(\text{under})} = 1\end{aligned}.

Therefore,

\begin{aligned} &\frac{V(\text{above})}{V(\text{above}) + V(\text{under})} \\ &= 1 - \frac{V(\text{under})}{V(\text{above}) + V(\text{under})} \\ &= 1 - \frac{\rho(\text{water})}{\rho(\text{ice})} = 1 - \frac{917}{10^3} = 0.083\end{aligned}.

That's equivalent to 8.3\,\%.

5 0
3 years ago
What is the name of the compound of MgO
MissTica
The correct answer would be <span>Magnesium oxide

Hope this helped :)

</span>
6 0
3 years ago
The speed of light is 3 x 108 m/s (300,000,000 m/s). A light wave has a wavelength of 400 nm (0.0000004 m). What is the frequenc
kirill115 [55]

Explanation:

velocity = wavelength × frequency

3×10⁸ = 400/10⁹ × frequency

frequency = 3 × 10¹⁵ /400

frequency = 75×10¹¹Hz

6 0
2 years ago
What organs are being affected from liver cancer and how?
yKpoI14uk [10]
The liver, because its liver cancer.. lol
The liver filters your blood, without it, your blood will stay 'dirty' and cannot do its jobs like it usually should be
5 0
3 years ago
How do u convert 7.68 cal/sec to kcal/min
stich3 [128]
<span>First you have to convert 7.68 cal/sec to cal/min to do that, just multiply by 60 So it will be 460.8 cal/min now convert that to kcal/min kcal = kilocalories = 1000 calories. so just divide by 1000 and youll have your answer in kcal/min </span>
5 0
4 years ago
Read 2 more answers
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